1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Katen [24]
2 years ago
15

Question

Chemistry
1 answer:
andrezito [222]2 years ago
3 0

The factors that affect the strength of electric or magnetic fields are loop count, the current, the wire size, and the presence of an iron core.

<h3>What is an electromagnetic field?</h3>

Electromagnetic field is defined as the field that is made up of both the electric and magnetic field that can help in conduction of electricity.

The factors that affect the strength of electric or magnetic fields include the following:

  • loop count,

  • the current,

  • the wire size, and

  • the presence of an iron core.

Learn more about magnetic field here:

brainly.com/question/14372859

#SPJ1

You might be interested in
Which of these elements has the smallest atomic radius?
Elodia [21]
Krypton. The atomic radius decreases as you go across a period.
5 0
3 years ago
Balance the following chemical
photoshop1234 [79]

Answer:

2FeBr3 + 3Na2S ➡️ Fe2S3 + 6NaBr

7 0
3 years ago
In the Reaction CuCl2 + 2 NaNO3 —&gt; Cu(NO3)2 + 2 Naci
Lunna [17]

Explanation:

The molar mass of the compounds are incorrect

5 0
2 years ago
3.0 cm x 4.0 cm x 1.0 cm<br><br>[?]cm^3​
CaHeK987 [17]

Explanation:

<em>Hi</em><em> </em><em>there</em><em>!</em><em>!</em>

<em>you</em><em> </em><em>asked</em><em> </em><em>to</em><em> </em><em>multiply</em><em> </em><em>these</em><em> </em><em>all</em><em> </em><em>right</em><em>,</em>

<em>you</em><em> </em><em>can</em><em> </em><em>simply</em><em> </em><em>multiply</em><em> </em><em>it</em><em> </em><em>,</em>

<em>=</em><em>3</em><em>cm</em><em> </em><em>×</em><em> </em><em>4</em><em> </em><em>cm</em><em> </em><em>×</em><em> </em><em>1</em><em>cm</em>

<em>=</em><em> </em><em>1</em><em>2</em><em>cm</em><em>^</em><em>2</em><em>×</em><em>1</em><em>cm</em><em> </em><em> </em><em> </em><em> </em><em>(</em><em>4</em><em>×</em><em>3</em><em>=</em><em>1</em><em>2</em><em>)</em>

<em>=</em><em> </em><em>1</em><em>2</em><em>cm</em><em>^</em><em>3</em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>(</em><em>1</em><em>2</em><em>×</em><em>1</em><em>=</em><em>1</em><em>2</em><em>)</em>

<em>Therefore</em><em>, </em><em> </em><em>the</em><em>answer is</em><em> </em><em>1</em><em>2</em><em> </em><em>cm</em><em>^</em><em>3</em><em>.</em>

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em>

4 0
3 years ago
The law of the conservation of mass must be obeyed in a chemical reaction. what do the atoms do during a reaction that shows the
Rainbow [258]
A balanced equation is a prime example of the law of the conservation of mass as the number of atoms in the reactants is consistent with the number of atoms in the reactants meaning the amount of matter has not changed and no mass has been created or destroyed hence obeying the law.
8 0
2 years ago
Other questions:
  • Who invented peroidic table
    8·2 answers
  • What is the theoretical yield of silver chloride?
    14·1 answer
  • Which of these choices best describes the interpretation of the following peak that may be recorded in a 1H NMR spectrum?
    8·1 answer
  • Calculate the pH is the<br> concentration of [H+] = 1.00x 10^-11
    9·1 answer
  • How do liquid water, ice, and water vapor differ from each other?
    9·2 answers
  • Where do plants get their energy?
    6·1 answer
  • Is Water a mixture or compound​
    10·1 answer
  • How many mass would be contained in 0.01mol of NaOH
    14·1 answer
  • Plss answer!!! I need help fast
    14·2 answers
  • Among the following scenarios, which best demonstrates resilience when confronted with stress?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!