Select the correct answer. One night, an ice storm strikes your town. When you go outside in the morning, your entire front walk
1 answer:
Sucrose will be the most effective. Hence, option D is correct.
<h3>What is sucrose?</h3>Sucrose is simply the chemical name for sugar, the simple carbohydrate we know and love that is produced naturally in all plants, including fruits, vegetables and even nuts.
When salt or sugar (a solute) is combined with water or ice (a solvent) and is evenly distributed, the freezing point is lowered.
→
Hence, sucrose will be the most effective.
Learn more about sucrose here:
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The volume of O₂ produced: 84.6 L
<h3>Further explanation</h3>Given
7.93 mol of dinitrogen pentoxide
T = 48 + 273 = 321 K
P = 125 kPa = 1,23365 atm
Required
Volume of O₂
Solution
Decomposition reaction of dinitrogen pentoxide
2N₂O₅(g)→4NO₂(g)+O₂ (g)
From the equation, mol ratio N₂O₅ : O₂ = 2 : 1, so mol O₂ :
= 0.5 x mol N₂O₅
= 0.5 x 7.93
= 3.965 moles
The volume of O₂ :
Answer: The molecular of the compound is,
Explanation:
The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:
where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.
We are given:
Mass of
Mass of
We know that:
Molar mass of carbon dioxide = 44 g/mol
Molar mass of water = 18 g/mol
For calculating the mass of carbon:
In 44 g of carbon dioxide, 12 g of carbon is contained.
So, in of carbon dioxide,
of carbon will be contained.
For calculating the mass of hydrogen:
In 18 g of water, 2 g of hydrogen is contained.
So, in of water,
of hydrogen will be contained.
For calculating the mass of oxygen:
Mass of oxygen in the compound =
To formulate the empirical formula, we need to follow some steps:
Step 1: Converting the given masses into moles.
Moles of Carbon =
Moles of Hydrogen =
Moles of Oxygen =
Step 2: Calculating the mole ratio of the given elements.
For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is moles.
For Carbon =
For Hydrogen =
For Oxygen =
Step 3: Taking the mole ratio as their subscripts.
The ratio of C : H : O = 2 : 3 : 1
Hence, the empirical formula for the given compound is
The empirical formula weight = 2(12) + 3(1) + 1(16) = 43 gram/eq
Now we have to calculate the molecular formula of the compound.
Formula used :
Molecular formula =
Therefore, the molecular of the compound is,