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blondinia [14]
2 years ago
15

Select the correct answer. One night, an ice storm strikes your town. When you go outside in the morning, your entire front walk

way is covered in a thick layer of ice. icy brick walkway in winter Your father asks you to walk to the corner store to buy a substance that you can add to the solid water to lower its freezing point and therefore melt it. When you get to the store, you read the labels on several containers holding substances that are soluble in water. For equal molar amounts, which substance will be the most effective? A. calcium chloride (CaCl2 → Ca2+ + 2Cl−) B. fructose (C6H12O6 → C6H12O6) C. potassium chloride (KCl → K+ + Cl−) D. sucrose (C12H22O11 → C12H22O11)
Chemistry
1 answer:
Sever21 [200]2 years ago
3 0

Sucrose will be the most effective. Hence, option D is correct.

<h3>What is sucrose?</h3>

Sucrose is simply the chemical name for sugar, the simple carbohydrate we know and love that is produced naturally in all plants, including fruits, vegetables and even nuts.

When salt or sugar (a solute) is combined with water or ice (a solvent) and is evenly distributed, the freezing point is lowered.

(C_{12}H_{22}O_{11} → C_{12}H_{22}O_{11})

Hence, sucrose will be the most effective.

Learn more about sucrose here:

brainly.com/question/24214907

#SPJ1

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The goal of this lesson:
mote1985 [20]

Answer:

1. The concentration of N₂O₄ decrease as the temperature of the system increased.

2. The formation of products was favored by the addition of heat.

3. The reaction going from right to left is exothermic.

4. N₂O₄ → 2NO₂; HR = +14 kcal.

Explanation:

Equation of the reaction is as follows: N₂O₄ ⇄ 2NO₂

The forward reaction proceeds with an increase in temperature. As the temperature of the reaction was increased, more of the N₂O₄ decomposed to form NO₂. Therefore, the concentration of N₂O₄ deceased.

2. The formation of products, that is the forward reaction leading to formation of NO₂ was favored by the addition of heat. Thus, with increase in temperature, the concentration of NO₂ increased.

3. An endothermic reaction is a type of reaction which requires energy input in the form of heat in order to proceed.

From the observations during the reaction, an increase in temperature by the addition of heat resulted in an increase in the forward reaction, therefore, the forward reaction is endothermic and the backward reaction is exothermic. Thus, the reaction in which colorless N₂O₄ is produced, is an exothermic reaction.

4. The change in enthalpy of a reaction is the difference in the heat content of reactants and products. For exothermic reactions, enthalpy change is negative, whereas for endothermic reactions, enthalpy change is positive.

The decomposition of  N₂O₄ to NO₂ is an endothermic reaction. Hence, the correct chemical equation is: N₂O₄ → 2NO₂; HR = +14 kcal.

7 0
3 years ago
A gas with a volume of 4.0 L at a pressure of 2.02 atm is allowed to expand to a volume of 12.0
Maurinko [17]
<h3>Answer:</h3>

P₂ = 0.67 atm

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Chemistry</u>

<u>Gas Laws</u>

Boyle's Law: P₁V₁ = P₂V₂

  • P₁ is pressure 1
  • V₁ is volume 1
  • P₂ is pressure 2
  • V₂ is volume 2
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] P₁ = 2.02 atm

[Given] V₁ = 4.0 L

[Given] V₂ = 12.0 L

[Solve] P₂

<u>Step 2: Solve</u>

  1. Substitute in variables [Boyle's Law]:                                                              (2.02 atm)(4.0 L) = P₂(12.0 L)
  2. [Pressure] Multiply:                                                                                           8.08 atm · L = P₂(12.0 L)
  3. [Pressure] [Division Property of Equality] Isolate unknown:                          0.673333 atm = P₂
  4. [Pressure] Rewrite:                                                                                           P₂ = 0.673333 atm

<u>Step 3: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs as our smallest.</em>

0.673333 atm ≈ 0.67 atm

4 0
3 years ago
What's the equation for the reaction of Trifluoro bromide with Ammonia gas. ( brainliest assured )​
sp2606 [1]

Answer:

Ammonium bromide can be prepared by the direct action of hydrogen bromide on ammonia. It can also be prepared by the reaction of ammonia with iron(II) bromide or iron(III) bromide, which may be obtained by passing aqueous bromine solution over iron filings.

Explanation:

please mark me as brainliest thank you

5 0
3 years ago
Discuss how the following factors determine the rate of electron transfer in biological systems:
Cloud [144]

Answer:check explanation

Explanation:

(a). HOW THE DISTANCE BETWEEN ELECTRON DONOR AND ACCEPTOR AFFECTS THE RATE OF ELECTRON TRANSFER IN BIOLOGICAL SYSTEM:

Distance between the acceptor and the donor can affect in two ways; short distance and long distance effect.

Short distance causes

electronic orbitals of donor and acceptor directly overlap whereas in LONG DISTANCE reactions this coupling is indirect because of

sequential overlaps of atomic orbitals of the donor, the intervening medium, and the orbitals of the acceptor.

(b). HOW REORGANIZATION ENERGY OF REDOX ACTIVE SPECIE SURROUNDING MEDIUM AFFECTS:

the reorganized energy does not depend on the pre-existing intra molecule electric field. The charge transferred inside the molecule interacts with its aqueous surroundings.

Reorganized energy can be calculated using Poisson-Boltzmann equation.

3 0
3 years ago
In many cases, a negatively charged compound (ex Cl-) will interact with a positively charged metal (ex Fe2 ). Usually we would
Zina [86]

Answer:

See Explanation

Explanation:

An ionic bond occurs due to electrostatic attraction between a positively charged ion and a negatively charged ion.

A metal and a ligand are bound by a coordinate covalent bond or a dative bond. This bond occurs due to donation of electron pairs from ligands to available orbitals on metals.

The formation of coordinate bonds is evident when neutral molecules or negative ions with non bonding electrons donate same to empty metal orbitals. This is sometimes shown by an arrow pointing from the ligands to the metal center.

For instance; tetraammine copper II ion is formed when four ammonia molecules donate a lone pair each to available vacant orbitals of the copper metal center to form [Cu(NH3)4]^2+.

6 0
3 years ago
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