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Leno4ka [110]
2 years ago
5

Fatty acids are a component of:

Chemistry
1 answer:
Ulleksa [173]2 years ago
7 0

According to the research, fatty acids, which are long molecules in the form of a hydrocarbon chain, are a component of lipids.

<h3>What are lipids?</h3>

They are hydrophobic and water-insoluble molecules that are formed from the esterification of alcohols with fatty acids.

Lipids are a vital part of the diet of living beings since many vitamins are assimilated in the presence of certain lipids and many fatty acids are essential for animal metabolism.

Therefore, we can conclude that according to the research,  fatty acids, which are long molecules in the form of a hydrocarbon chain, are a component of lipids.

Learn more about the lipids here: brainly.com/question/17352723

#SPJ12

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How many grams are there in 3.34 mol HCl?
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If 5.0 grams of sucrose, C12H22O11, are dissolved in 10.0 grams of water, what will be the boiling point of the resulting soluti
GaryK [48]

Answer : The boiling point of the resulting solution is, 100.6^oC

Explanation :

Formula used for Elevation in boiling point :

\Delta T_b=i\times k_b\times m

or,

T_b-T^o_b=i\times k_b\times \frac{w_2\times 1000}{M_2\times w_1}

where,

T_b = boiling point of solution = ?

T^o_b = boiling point of water = 100^oC

k_b = boiling point constant  = 0.52^oC/m

m = molality

i = Van't Hoff factor = 1 (for non-electrolyte)

w_2 = mass of solute (sucrose) = 5.0 g

w_1 = mass of solvent (water) = 10.0 g

M_2 = molar mass of solute (sucrose) = 342.3 g/mol

Now put all the given values in the above formula, we get:

(T_b-100)^oC=1\times (0.52^oC/m)\times \frac{(5.0g)\times 1000}{342.3\times (10.0g)}

T_b=100.6^oC

Therefore, the boiling point of the resulting solution is, 100.6^oC

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5 0
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