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Savatey [412]
2 years ago
11

What can we say about elements?

Physics
2 answers:
Andrew [12]2 years ago
7 0

Answer:

I would say that your best answer would be C.

I'm not too sure about this, but it's the best answer on there

Explanation:

Hope this helps you.

gtnhenbr [62]2 years ago
7 0
<h3>Answer:</h3>

C. They can be bonded together to create different substances.

<h3>Explanation:</h3>

Elements are the simplest substances that can get without losing their properties. They can be found on the periodic table.

To help answer this question we can break down each answer choice.

Choice A

Answer A cannot be correct simply because of the definition of an element. A substance of a pure element cannot be broken down into any simpler substance. The only thing beyond an element is subatomic particles like protons and electrons, which are not considered substances. So elements are the simplest substances that exist.

Choice B

Many elements are found in nature. It would be impossible to live if elements were not naturally occurring. For example, oxygen is an element. Oxygen is found naturally in the atmosphere and is replenished by photosynthesis and the carbon cycle. Additionally, all life is carbon-based, so of course, carbon is also naturally occurring.

Choice C

Chemical compounds and substances surround us every day. Just as we need oxygen to breathe, carbon dioxide is also an important part of life. Carbon dioxide is a substance created by the bonding of carbon and two oxygen atoms when we breathe out. So, it is true that elements can be boned to create substances.

Choice D

As stated in the explanation for choice B, elements can be found naturally. There are some elements created in a lab like Technetium, but others such as sulfur and oxygen are not created in labs.

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If this standing wave is 48.8 meters long from end to end, what is the wavelength?
Mrrafil [7]

The wavelength of a standing wave is 8.13 m.

<h3>What is a wavelength?</h3>

The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.

The wavelength is also defined as the distance between two locations in a wave that have the same oscillation phase.

The given data in the problem is;

String length(L)= 48.8 metere

Wavelength(λ)=?

The length of the wave having n nodes is found as;

L=nλ

Substitute the given value;

48.8 = 6λ

λ= 8.13 m

Hence, the wavelength of a standing wave is 8.13 m.

To learn more about the wavelength, refer to the link;

brainly.com/question/7143261

#SPJ1

6 0
2 years ago
What type of energy is thermal energy? A. Sound energy B. Chemical energy C. Kinetic energy D. Nuclear energy
Nadya [2.5K]

Answer:

kinetic energy

Explanation:

7 0
3 years ago
A 0.60 kg rubber ball has a speed of 2.0 m/s at point A, and kinetic energy of 7.5 J at point
aliina [53]
<span>Let's first off calculate the kinetic energy using the formula 1/2MV^2. Where the mass, M, is 0.6Kg. And speed, V, is 2. Hence we have 1/2 * 0.6 * 2^2 = 1.2J. Since kinetic energy is energy due to motion; hence at point B the rubber has a KE of 1.2J and not 7.5J. So I would say that only the Mass and speed is actually true; While it's kinetic energy is not true.</span>
7 0
4 years ago
Two blocks with masses 1 and 2 are connected by a massless string that passes over a massless pulley as shown. 1 has a mass of 2
Bess [88]

Answer:

The acceleration of M_2 is  a =  0.7156 m/s^2

Explanation:

From the question we are told that

    The mass of first block is  M_1 =  2.25 \ kg

    The angle of inclination of first block is  \theta _1 =  43.5^o

    The coefficient of kinetic friction of the first block is  \mu_1  = 0.205

      The mass of the second block is  M_2 = 5.45 \ kg

     The angle of inclination of the second block is  \theta _2 =  32.5^o

      The coefficient of kinetic friction of the second block is \mu _2 = 0.105

The acceleration of M_1 \ and\  M_2 are same

The force acting on the mass M_1 is mathematically represented as

     F_1 = T -  M_1gsin \theta_1 - \mu_1 M_1 g cos\theta_1

=> M_1 a = T -  M_1gsin \theta_1 - \mu_1 M_1 g cos\theta_1

Where T is the tension on the rope

The force acting on the mass M_2 is mathematically represented as    

  F_2 =  M_2gsin \theta_2 - T -\mu_2 M_2 g cos\theta_2

   M_2 a =  M_2gsin \theta_2 - T -\mu_2 M_2 g cos\theta_2

At equilibrium

  F_1 =  F_2

So

 T -  M_1gsin \theta_1 - \mu_1 M_1 g cos\theta_1 =M_2gsin \theta_2 - T -\mu_2 M_2 g cos\theta_2

making a the subject of the formula

    a =  \frac{M_2 g sin \theta_2 - M_1 g sin \theta_1 - \mu_1 M_1g cos \theta - \mu_2 M_2 g cos \theta_2 }{M_1 +M_2}

substituting values a =  \frac{(5.45) (9.8) sin (32.5) - (2.25) (9.8) sin (43.5) - (0.205)*(2.25) *9.8cos (43.5) - (0.105)*(5.45) *(9.8) cos(32.5) }{2.25 +5.45}

    => a =  0.7156 m/s^2

     

3 0
4 years ago
A particle of mass m = 13 kg moves in space under the action of a conservative force. Its potential energy is given by PE = 2xyz
Helen [10]

Answer:

F_{x} = -12 N ,  F_{y} = -80 N  and  F_{z} = - 44 N

Explanation:

The force is related to the potential energy by the formula

      F = -Δ U = - ( \frac{dU}{dx} i ^ + \frac{dU}{dy} j ^ + \frac{dU}{dz}k ^)

It indicates the potential energy

      U = 2xyz + 3z² + 4yx + 16

To solve this problem let's make the derivatives, to find each component of the force

       \frac{dU}{dx} = 2yz + 0 + 4y  + 0 = 2yz + 4y

       \frac{dU}{dx} = 2xz + 0 + 4x  + 0 = 2xz + 4x

      \frac{dU}{dx} = 2xy + 3 2z + 0 +0 = 2xy + 6z

We look for the expression for the force in each axis

      F_{x} = - 2yz - 4y

      F_{y} = -2xz -4x

      F_{z} = -2xy -6z

We calculate at the point P = (20 i ^ + 1j ^ + 4 k ^) m

        F_{x} = - 2 1 4 - 4 1

        F_{x} = -12 N

        F_{y} = - 2 20 4 - 4 20

        F_{y} = -80 N

        F_{z}= - 20 1 - 6 4

        F_{z} = - 44 N

We put together the expression for strength

        F = (-12 i ^ - 80j ^ -44k ^) N

5 0
4 years ago
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