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2 years ago

What is the net force needed to lift a full grocery sack (weighing 210 N) uniformly? What is the net force

Physics

1 answer:

Stella [2.4K]2 years ago

8 0

The net force needed to lift a full grocery sack uniformly is 32.115 N.

<h3>What is Net force?</h3>

When two or more forces are acting on the system of objects, then the to attain equilibrium, net force must be zero.

Given the weight of sack W = 210N and the acceleration a = 1.5m/s².

The mass of the sack will be

m = Weight / acceleration due to gravity

m = 210 N/9.81 m/s²

m = 21.41 kg

Using Newton's second law, the net force will be

F = mass x acceleration

F= 21.41 x 1.5

F = 32.115 N

Thus, the net force is 32.115 N.

Learn more about net force.

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Answer:

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Considering d

The force providing the centripetal force is the tension on the string

Considering e

The force providing the centripetal force is the force of gravity between the earth and the sun

Explanation:

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Explanation:

From the question we are told that

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The drag coefficient is $C__{D}} = 0.5$

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The acceleration due to gravity in Mars is $g_m = 3.689 \ m/s^2$

Generally the Mars atmosphere density is mathematically represented as

$\rho_m = 0.71 * \rho$

=> $\rho_m = 0.71 * 1.2$

=> $\rho_m = 0.852 \ kg/m^3$

Generally the drag force on the rover and the parachute is mathematically represented as

$F__{D}} = m * g_{m}$

=> $F__{D}} = 2270 * 3.689$

=> $F__{D}} = 8374 \ N$

Gnerally this drag force is mathematically represented as

$F__{D}} = C__{D}} * A * \frac{\rho_m * v^2 }{2}$

Here A is the frontal area

$A = \frac{2 * F__D }{ C__D} * \rho_m * v^2 }$

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