Answer:
A. Zero
Explanation:
The force on a coil of N turns, enclosing an area, A and carrying a current I in the presence of a magnetic field B, is :
F = N * I * A * B * sinθ
Where θ is the angle between the normal of the enclosed area and the magnetic field.
Since the normal of the area is parallel to the magnetic field, θ = 0
Hence:
F = NIABsin0
F = 0 or Zero
Answer:
1J
Explanation:
Work done = force × distance
1 × 1 = 1
Work done = 1J
J = Joules
Answer:
10N right
Explanation:
First, we need to find the base of the triangle to find the force acting on the right of the object.
- We have been given the hypotenuse and we need to find the adjacent, so we are using cos
- SOH, CAH, TOA
- cos(θ) = adjacent ÷ hypotenuse
Next, sub in the values (we don't know the adjacent so i've called it x):
To find x, we need to multiply both sides by 60
Now we know all the forces, we can work out the net force:
- Both of the 40N cancel out because they are opposite forces
- The force on the right of the object is 10N stronger than the force on the left (30N - 20N), so the object would move to the right
Your question has been heard loud and clear.
Well it depends on the magnitude of charges. Generally , when both positive charges have the same magnitude , their equilibrium point is towards the centre joining the two charges. But if magnitude of one positive charge is higher than the other , then the equilibrium point will be towards the charge having lesser magnitude.
Now , a negative charge is placed in between the two positive charges. So , if both positive charges have same magnitude , they both pull the negative charge towards each other with an equal force. Thus the equilibrium point will be where the negative charge is placed because , both forces are equal , and opposite , so they cancel out each other at the point where the negative charge is placed. However if they are of different magnitudes , then the equilibrium point will be shifted towards the positive charge having less magnitude.
Thank you
