Orbit circumference
<span>= 2 pi *1.9*10^7 miles </span>
<span>time for orbit trip = 2.9*10^7 s </span>
<span>speed = 2 pi *1.9 / 2.9 miles/second </span>
<span>= 4.12 miles/second </span>
<span>You did not say what units </span>
<span>in miles per hour, multiply by 3600 and get </span>
<span>14,820 miles/hour</span>
Answer:
yes; yes
Explanation:
Phases of the moon refers to the shapes of the moon due to the lit part of it visible from the Earth. On a new moon day, the moon comes between the sun and the earth such that the lit portion is not visible from the Earth. On a full moon day, the earth comes between the sun and the moon and the whole lit part is visible.
When one would view the earth from the moon, the earth would also be visible as going through the phases. The order would be reversed. Understand this with the following example, On a new moon day, the Earth would be visible completely lit from the moon. So it will be full Earth day on the moon. On a full moon day, the lit side of the Earth would be completely away and hence, from the moon, new earth would be there.
Answer:
Explanation:
Remark
Let's start with the second question first. If the two forces aren't balanced, the truck will move in some direction. So the downward force of the truck must equal the upward force provided by the pavement pushing up.
Mass of truck = 9500 kg. Remember mass is directionless and it is not a force or weight. That truck would have a mass of 9500 kg anywhere in the universe.
Givens
m = 9500
a = 9.8
Force or weight = ?
Formula and Solution
F = m * a
F = 9500 * 9.8
F = 93100 N
Comment
That force does have a direction. It is down.
The balancing force (you call it the reaction force) going upward is 93100 N
Answer:
t all= 30h
Explanation:
In this problem the speed of the plane is constant, so we can use the equations of uniform rectilinear motion, the definition of average speed is the distance traveled between the time taken.
v = d / t
Let's calculate each distance
First part of the trip
v₁ = d₁ / t₁
d₁ = v₁ t₁
d₁ = 120 t₁
Second part of the trip
v₂ = d₂ / t₂
d₂ = v₂ t₂
d₂ = 180 t₂
Total trip
v₃ = d₃ / t₃
d₃ = v₃ t₃
d₃ = 170 t₃
The total travel distance is the sum of each distance and the total time is the initial time of 5 h plus the time of the second part (t2)
d₁ + d₂ = 170 t₃
120 5 + 180 t₂ = 170 (5 + t₂)
Let's solve
600 + 180 t₂ = 850 +170 t₂
t₂ (180 -170) = 850 - 600
10 t₂ = 250
t₂ = 25 h
Therefore, the total travel time is
t all= 5 +25 = 30h
