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1 year ago

An object is placed at 0 on a number line. It moves 3 units to the right, then 4 units to the left, and then 6 units to the

Physics

2 answers:

Archy [21]1 year ago

6 0

<—————->
0
+3. =3
-4. = -1
+6 = 5

the answer is 5

o-na [289]1 year ago

5 0

Answer: 5

Explanation: If you use a real graph it could be easier to check, but here’s it the easy way.

You start at 0, add 3 as you are going right on the right , subtract 4 as you are going left, then again add 6 as you are going right, and you should get 5.

0+3= 3

3-4= -1

-1+6= 5

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Calculate the height from from which a body is released from rest if its velocity just before hitting the ground is30m\s

Kamila [148]

Answer:

height = 45 m

Explanation:

Initial velocity = 0 m/s

Final velocity = 30 m/s

Acceleration due to gravity = +10m/s^2 ( because ball is going down )

Using the eqn of motion

${v}^{2} - {u}^{2} = 2gh$

where v= final velocity ; u = initial velocity ; g = acceleration due to gravity ; h = height

So,

${30}^{2} - {0}^{2} = 2 \times 10 \times h$

$= > 20h = 900$

$= > h = \frac{900}{20} = 45$

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3 years ago

Hypothetically, suppose our resistance in part I was 200 ohms. Quantitatively calculate the impact of a 1 Ohm ammeter resistance

Slav-nsk [51]

Answer:

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Explanation:

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3 years ago

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3 years ago

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3 years ago

Read 2 more answers

The time, t, required to drive a fixed distance varies inversely as the speed, r. It takes 3 hr at a speed of 14 km/h to driv

kenny6666 [7]

Answer:

time taken with speed 23 km/h will be 1.8 hours or 1 hour 48 minutes

Explanation:

Given:

Time is inversely proportional to the speed

mathematically,

t ∝ (1/r)

let the proportionality constant be 'k'

thus,

t = k/r

therefore, for case 1

time = 3 hr

speed = 14 km/hr

3 = k/14

also,

for case 2

let the time be = t

r = 23 km/h

thus,

we have

t = k/23

on dividing equation 2 by 1

we get

$\frac{t}{3}=\frac{k/23}{k/14}$

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3 years ago