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zlopas [31]
2 years ago
13

How many moles of naoh will react with 13.5 moles of k3po4

Chemistry
1 answer:
Alona [7]2 years ago
8 0

Answer: 40.5 mol

Explanation:

Since this is a double replacement reaction, the unbalanced equation is something like follows:

\text{K}_{3}\text{PO}_{4}+\text{NaOH} \longrightarrow \text{KOH}+\text{Na}_{3}\text{PO}_{4}

Balancing this equation,

\text{K}_{3}\text{PO}_{4}+3\text{NaOH} \longrightarrow 3\text{KOH}+\text{Na}_{3}\text{PO}_{4}

From this equation, we can conclude that for every 3 moles of sodium hydroxide consumed, 1 mole of potassium phosphate is consumed.

This means the answer is 13.5(3)=<u>40.5 mol</u>

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How much heat will be absorbed by a 26.3 g piece of aluminum (specific heat = 0.930 J/g・°C) as it changes temperature from 23.0°
kotykmax [81]

Answer:

\boxed {\boxed {\sf 1076.196 \ Joules}}

Explanation:

Since we are given the mass, specific heat, and temperature, we should use the following formula for heat energy.

q=mc\Delta T

The mass of the aluminum is 26.3 grams. Its specific heat is 0.930 Joules per gram degree Celsius. We need to find the change in temperature.

  • The change in temperature is the difference between the initial temperature to the final temperature.
  • The temperature changes <em>from</em> 23.0°C <em>to</em> 67.0°C, so the initial is 23 degrees and the final is 67 degrees.
  • ΔT= final temperature - initial temperature
  • ΔT= 67°C - 23°C
  • ΔT= 44°C

Now we know all the values.

  • m= 26.3 g
  • c= 0.930 J/g °C
  • ΔT= 44°C

Substitute the values into the formula.

q= (26.3 \ g}) \times (0.930 \ J/g \textdegree C) \times (44 \textdegree C)

Multiply the first two numbers together. The units of grams cancel.

q= 24.459 \ J/ \textdegree C \times 44 \textdegree C

Multiply again. This time, the units of degrees Celsius cancel.

q=1076.196 \ J

<u>1076.196 Joules</u> of heat will be absorbed by the piece of aluminum.

4 0
3 years ago
Explain why it is not a good idea to throw an arsenal canon to fire. Which gas law applies?
Feliz [49]

Answer:

is a class of heavy military ranged weapons built to launch munitions far beyond the range and power of infantry firearms. This development continues today; modern self-propelled artillery vehicles are highly mobile weapons of great versatility generally providing the largest share of an army's total firepower.

Explanation:

it could explode

6 0
3 years ago
In chemistry what is nickle (II) nitrate solution mixed with a sodium hydroxide solution
AlladinOne [14]

Answer:

I hope this will help you and Please mark me as Brilliant

Explanation:

Approximately 2 mL of Solution A (on the left) is added to a sample of Solution B (on the right) with a dropping pipet. If a precipitate forms, the resulting precipitate is suspended in the mixture. The mixture is then stirred with a glass stirring rod and the precipitate is allowed to settle for about a minute.

Solution A: 0.5 M sodium hydroxide, colorless

Solution B: 0.2 M nickel(II) nitrate, green

Precipitate: light green

Ni(NO3)2(aq) + 2 NaOH(aq) —> Ni(OH)2(s) + 2 NaNO3(aq)

Credits: 

Design

Kenneth R. Magnell Central Michigan University, Mt. Pleasant, MI 48859

John W. Moore University of Wisconsin - Madison, Madison, WI 53706

Video

Jerrold J. Jacobsen University of Wisconsin - Madison, Madison, WI 53706

Text

Kenneth R. Magnell Central Michigan University, Mt. Pleasant, MI 48859

6 0
3 years ago
Cu2O + C-&gt;<br> Cu + CO2<br> Balance the above reaction by writing in the correct coefficient.
baherus [9]

Answer:

2 Cu2O + C = 4 Cu + CO2

Explanation:

CU2O has 2 coefficient

C has 1 coefficient

Cu has 4 coefficient

CO2 has 1 coefficient

Balance Equation 2 Cu2O + C = 4 Cu + CO2

6 0
3 years ago
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I need friends please be my friend I play clash of clans and valorant im also on discord
svet-max [94.6K]

Answer:

of course

Explanation:

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3 years ago
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