Question

How many moles of naoh will react with 13.5 moles of k3po4

Answer 1

Answer: 40.5 mol

Explanation:

Since this is a double replacement reaction, the unbalanced equation is something like follows:

$\text{K}_{3}\text{PO}_{4}+\text{NaOH} \longrightarrow \text{KOH}+\text{Na}_{3}\text{PO}_{4}$

Balancing this equation,

$\text{K}_{3}\text{PO}_{4}+3\text{NaOH} \longrightarrow 3\text{KOH}+\text{Na}_{3}\text{PO}_{4}$

From this equation, we can conclude that for every 3 moles of sodium hydroxide consumed, 1 mole of potassium phosphate is consumed.

This means the answer is 13.5(3)=40.5 mol