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alex41 [277]
3 years ago
6

Which statements about radiocarbon dating are true?

Physics
2 answers:
seropon [69]3 years ago
8 0
Radiocarbon saying assume the half life for radioistopes change over time. The half life of C -14 is 5730 years
Reika [66]3 years ago
8 0

both are the correct answers:

B. It's useful for dating some organic (once-living) things.

D. It's useful for dating some materials that are thousands of years old.

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A 2.5 kg cat is resting on top of a bookshelf that is 3 meters high. What is the cats gravitational potential energy relative to
erma4kov [3.2K]

Answer:

The answer to your question is Ep = 73.6 Joules

Explanation:

Data

mass = 2.5 kg

height = 3 m

gravity = 9,81 m/s²

Potential energy = ?

Potential energy is the energy stored in an object due to its position, the highest the object be, the highest the potential energy.

Formula

Pe = mgh

Substitution

Ep = (2.5)(9.81)(3)

Simplification and result

Ep = 73.6 Joules

4 0
3 years ago
How are mass and free fall related to acceleration?
Dmitrij [34]

Explanation:

The acceleration of the object equals the gravitational acceleration. The mass, size, and shape of the object are not a factor in describing the motion of the object. So all objects, regardless of size or shape or weight, free fall with the same acceleration hope that helps

4 0
2 years ago
Read 2 more answers
Most new jobs in the United States will be in the _____.
Kazeer [188]

in the service producing sector

6 0
3 years ago
A plane is flying a circular path at a speed of 55.0 m/ s, with a radius of 18.3 m. The centripetal force needed to maintain thi
Nadusha1986 [10]

The plane has a centripetal acceleration <em>a</em> of

<em>a</em> = <em>v</em> ²/<em>r</em>

where <em>v</em> is the plane's tangential speed and <em>r</em> is the radius of the circle. By Newton's second law,

<em>F</em> = <em>mv</em> ²/<em>r</em>

Solve for the mass <em>m</em> :

<em>m</em> = <em>Fr</em>/<em>v</em> ² = (3000 N) (18.3 m) / (55.0 m/s)² ≈ 18.1 kg

7 0
3 years ago
A 2500‐kg vehicle traveling at 25 m/s can be stopped by gently applying the breaks for 20 seconds. What is the average force sup
katen-ka-za [31]
Momentum = (mass) x (speed)

Change in momentum = (force) x (time)

The initial momentum is (mass) x (speed) = 2500x 25 = 62,500 kg-m/s.

Since you want to <u>stop</u> the vehicle, that number is also the required <em>change</em>
in momentum ... you want the vehicle to wind up with zero momentum.

62,500 = (force) x (time) = 20 x force

Divide each side by 20 :

force = 62,500 / 20 = <em>3,125 newtons </em>
3 0
3 years ago
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