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2 years ago

Cisco what three best practices can help defend against social engineering attacks?

Engineering

1 answer:

SOVA2 [1]2 years ago

4 0

The three best practices that can help defend against social engineering attacks are:

Do not provide password resets in a c.ha.t window.
Resist the urge to click on enticing web links.
Educate employees regarding policies.

<h3>What is Social Engineering?</h3>

This refers to the art of manipulation of people through social interactions with the aim of getting access to sensitive information that gives unauthorized access.

Hence, we can see that some of the best practices that can be used to defend against social engineering include not clicking on suspicious links, educating people about the dangers, etc.

Read more about social engineering here:

brainly.com/question/26072214

#SPJ12

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3 years ago

Design a fundamental mode asynchronous finite state machine that accepts input pair, A and B. The AB input sequence 00, 01,11, 1

dybincka [34]

Answer:

See explaination

Explanation:

A Finite state machines can be synchronous or asynchronous. The operation of asynchronous state machines does not require a clock signal. An Asynchronous state machine is classified basically on their operating mode, such as the fundamental mode, pulse mode or burst mode. An asynchronous state machine can have stable and transient states.

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2 years ago

A 30 mm thick AISI 1020 steel plate is sandwiched between two 10 mm thick 2024-T3 aluminum plates and compressed with a bolt and

denis-greek [22]

Answer:

275 MPa

Explanation:

Regardless of what it is holding, the stiffness of a bolt depends on its own material properties and geometry.

The stiffness is:

$k = E * \frac{A}{l}$

I assume this one is made of steel, because regular bolts are steel.

The Young's modulus for steel is E = 210 GPa

The longitude is given. (But note that in a real application you have to consider the length up to the nut.)

The section is (using the nominal diameter of 10 mm)

$A = \frac{\pi * d^2}{4} = \frac{\pi * 0.01^2}{4} = 7.85e-5 m^2$

Then:

$k = 2.1e11 * \frac{7.85e-5}{0.06} = 275e6 Pa = 275 MPa$

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3 years ago

Can i eat unhealthy while i’m drinking green tea for weight loss ?

Zina [86]

Answer:I don't think it's a better idea to eat unhealthy food while having green tea because it will act as a strumbling rock in your attempt of getting weight loss.

Explanation:I don't say you have to mark my ans as brainliest but if ypu think it has really helped you plz don't forget to thank me...

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2 years ago

Read 2 more answers

Consider the diffusion of water vapor through a polypropylene (PP) sheet 1 mm thick. The pressures of H2O at the two faces are 3

Neko [114]

Answer:

$\boxed{0.000000266 \frac {cm^{3}.STP}{cm^{2}.s}}$

Explanation:

Diffusion flux of a gas, J is given by

$J=P_m\frac {\triangle P}{\triangle x}$ where $P_m$ is permeability coefficient, $\triangle$ P is pressure difference and x is thickness of membrane.

The pressure difference will be 10,000 Pa- 3000 Pa= 7000 Pa

At 298 K, the permeability coefficient of water vapour through polypropylene sheet is $38\times 10^{-13}(cm^{3}. STP)(cm)/(cm^{2}.s.Pa)$

Since the thickness of sheet is given as 1mm= 0.1 cm then

$J=38\times 10^{-13}(cm^{3}. STP)(cm)/(cm^{2}.s.Pa)\times \frac {7000 pa}{0.1cm}=0.000000266 \frac {cm^{3}.STP}{cm^{2}.s}$

Therefore, the diffusion flux is $\boxed{0.000000266 \frac {cm^{3}.STP}{cm^{2}.s}}$

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2 years ago