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hram777 [196]
2 years ago
11

Struggling with this, pls answer:( Brainliest to the (FIRST) right answer

Physics
1 answer:
riadik2000 [5.3K]2 years ago
4 0

Answer:

c. a and c

Explanation:

ammeters are connected in series to measure charge/current

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Which of the following exhibits parabolic motion? a. a person diving into a pool from a diving board b. a space shuttle orbiting
Crazy boy [7]

Answer: a stone thrown into a lake

Explanation:

The option that exhibits parabolic motion is a stone that is thrown into a lake.

Projectile motion is a form of motion that is seen when a particular object is thrown towards the surface fo the Earth. Such objects are acted upon by gravity.

6 0
3 years ago
A 0.017-kg acorn falls from a position in an oak tree that is 18.5 meters above the ground.
Marianna [84]

Answer:

Part a)

Final speed of the corn is 19.05 m/s

Part b)

Kinetic energy of the corn is 3.1 J

Explanation:

Part a)

As we know that the initial position of the corn is

h = 18.5 m

now we also know that it will fall from rest and moving under constant acceleration so we will have

v_f^2 - v_i^2 = 2 a d

v_f^2 - 0 = 2(9.81)(18.5)

v_f = 19.05 m/s

Part b)

Kinetic energy of the corn is given as

K = \frac{1}{2}mv^2

K = \frac{1}{2}(0.017)(19.05)^2

K = 3.1 J

4 0
4 years ago
A 80 kg parent and a 20 kg child meet at the center of an ice rink. They place their hands together and push. The parent pushes
Ymorist [56]

Answer:

force acting on the parent = 25 N .

Explanation:

According to third law of Newton , there is equal and opposite reaction to every action . Here force by the parent on child is action and the force by child on parent is reaction . The former is given as 25 N so force by child on parent will also be 25 N .

Answer is 25 N .

4 0
3 years ago
A small, 2.00-mm-diameter circular loop with R = 1.00×10^−2 Ω is at the center of a large 100-mm-diameter circular loop. Both lo
Assoli18 [71]

Answer:

i=2.1\times 10^{-8}}\ A

Explanation:

Given that

Diameter of small loop d= 2 mm  or r=1 mm

Diameter of large loop D= 100 mm  or R=50 mm

We know that induce emf given as

\varepsilon =-\dfrac{d\phi }{dt}

\varepsilon =-\dfrac{BA }{dt}

B=\dfrac{\mu _oI}{2\pi R}

\varepsilon =-\pi \times r^2\times \dfrac{4\pi \times 10^{-7}(I_2-I_1)}{2\pi Rdt}

\varepsilon =-\pi \times 0.001^2\times \dfrac{4\pi \times 10^{-7}(-1-1)}{2\pi \times 0.05\times 0.1}

\varepsilon =2.1\times 10^{-10}\ V

So induce current

i=emf/R

i=\dfrac{2.1\times 10^{-10}}{10^{-2}}\ A

i=2.1\times 10^{-8}}\ A

5 0
3 years ago
What is the current in a 160V circuit if the resistance is 200?
Novosadov [1.4K]
V=120 v=IR
R=2ø
I = ? I= v/r
I= 120r/ 10
Answer 12Amps
4 0
3 years ago
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