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hram777 [196]
1 year ago
11

Struggling with this, pls answer:( Brainliest to the (FIRST) right answer

Physics
1 answer:
riadik2000 [5.3K]1 year ago
4 0

Answer:

c. a and c

Explanation:

ammeters are connected in series to measure charge/current

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How large a current would a very long, straight wire have to carry so that the magnetic field 2.20 cm from the wire is equal to
choli [55]
Biot-Savart Law - Magnetic field around a straight conductor carrying a current I.

B = μ_0 I/2πr

where:
B is strength of magnetic field in T.
μ_0 is permeability of free space = 1.25664 x 10^ -6 T-m/A.
I is current in A.
r is distance from conductor in m.

<span>So I = 2πrB /μ_0</span>
6 0
2 years ago
A cylinder of mass 8.0 kg rolls without slipping on a horizontal surface. At a certain instant its center of mass has a speed of
olganol [36]

Answer:

b

Explanation:

determine the rotational kinetic energy about it's center of mass

8 0
3 years ago
A small bead of mass m is constrained to slide without friction inside a circular vertical hoop of radius r which rotates about
Stolb23 [73]

Answer:

Explanation:

The bead is moving on a vertical circular path so it must have a centripetal force towards the centre.

This force is equal to m v² / r

v is velocity of bead and r is radius of the circular path.

The vertical hoop is also rotating about a vertical axis passing through the centre at frequency f so the bead will experience a cetrifugal force due to rotation of the hoop. Its value is

m ω² r . Only at the point o degree and 180 degree , these forces are opposite to each other so at these points , the bead will be in equilibrium .

mv² / r = m ω² r

v² = ω² r²

v = ω r

= 2π f r

= 2 x 3.14 x 2 x 0.22

v = 2.76 m /s

For the bead to rise upto point θ = 90 degree , height achieved is radius R

required velocity = √ 2gR

= √ 2x 9.8x.22

= 2.076 m/s

This velocity is less than the velocity calculated earlier so the bead will be able to ride the required height.

v = 2.76 m/s

5 0
2 years ago
You have just landed on Planet X. You take out a ball of mass 101 g , release it from rest from a height of 16.0 m and measure t
IRINA_888 [86]

Answer:

0.3817 N

Explanation:

Remark

One thing is certain: the ball has a mass of 101 grams wherever it is in the universe. That is not true of the force. The force on the moon is a whole lot less than it is on earth, and maybe planet x as well.

Givens

m = 101 g

vi = 0       That's what at rest means.

t = 2.91 s

d = 16 m

F= ?

Formulas

d = vi*t + 1/2*a * t^2

Force = m * a

Solution

16 = 0 + 1/2 a * 2.91^2

16 = 4.234 a                       Divide by 4.234

16/4.234 = a

a = 3.779

F = m * a

a = 3.779

m = 101 g = 1 kg / 1000 grams

m = 0.101 kg

F = 0.101 * 3.779

F = 0.3817N

8 0
2 years ago
How much energy is needed to perform 300 J of work?
4vir4ik [10]
I think this is the answer hope it helps

3 0
3 years ago
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