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d1i1m1o1n [39]
2 years ago
15

I think it’s gas but I’m not sure.

Physics
1 answer:
malfutka [58]2 years ago
4 0

Answer:

Liquid

Explanation:

The substance will be liquid because the gas form will be 100° Celsius. So, it is not gas instead it is liquid. Solid is not the answer because it has to be 0° C

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I need so much help 50 points!!!!!!<br><br>complete the graph
motikmotik

<u>First Symbol </u>: Cobalt (Co)

Its Group Number - 9

Its Period Number - 4

Its Family Name - Transition Metal

<u>Second Symbol</u> : Silicon (Si)

Its Group Number - 14

Its Period Number - 2

Its Family Name - Semiconductor

<u>Third Symbol</u> : Astatine (At)

Its Group Number - 17

Its Period Number - 6

Its Family Name - Halogen

<u>Fourth Symbol </u>: Magnesium (Mg)

Its Group Number - 2

Its Period Number - 3

Its Family Name - Alkaline Earth Metal

<u>Fifth Symbol</u> : Xenon (Xe)

Its Group Number - 18

Its Period Number - 5

Its Family Name - Noble Gas

6 0
3 years ago
The Cosmoclock 21 Ferris wheel in Yokohama City, Japan, has a diameter of 100 m. Its name comes from its 60 arms, each of which
emmainna [20.7K]

Answer:

Explanation:

A ) angular velocity ω = 2π / T

= 2 x 3.14 / 60

= .10467 rad / s

linear velocity v = ω R

=  .10467 x 50

= 5.23 m / s

centripetal force = m v² / R

= mg v² / gR

= 834 x 5.23² / 9.8 x 50

= 46.55 N

B )

apparent weight

= mg - centripetal force

= 834 - 46.55

= 787.45 N

C ) apparent weight

= mg + centripetal force

= 834 + 46.55

= 880.55 N.

D )

For apparent weight to be zero

centripetal force = mg

mg = mv² / R

v² = gR

= 9.8 x 50

= 490

v = 22.13 m /s

time period of revolution

= 2π R /v

2 x 3.14 x 50 / 22.13

= 14.19 s  

8 0
4 years ago
A cell phone sending a text message what kinda energy is to the scenario?
creativ13 [48]

Answer:

low powered radio frequency (RF) energy

7 0
3 years ago
These clouds are low in the sky and tend to cover most of the sky. Which weather conditions are most likely to occur when you se
arsen [322]

Answer:

Light rain, sleet, or snow

Explanation:

pls brainlyest

4 0
3 years ago
Read 2 more answers
In an experiment Rahul burnt 4 kg fuel and the heat produced was measured to be 160,000 kJ and Raj burnt 2 kg of fuel and heat p
Gnesinka [82]

Answer:

The net calorific value of the fuel 1 is 40000 kilojoules per kilogram.

The net calorific value of the fuel 2 is 50000 kilojoules per kilogram.

Explanation:

The net calorific value is equal to the heat produced (Q), in kilojoules, divided by the mass of the burnt fuel (m). We proceed to calculate the net calorific value of each fuel:

Fuel 1 (m = 4\,kg, Q = 160000\,kJ)

L = \frac{160000\,kJ}{4\,kg}

L = 40000\,\frac{kJ}{kg}

The net calorific value of the fuel 1 is 40000 kilojoules per kilogram.

Fuel 2 (m = 2\,kg, Q = 100000\,kJ)

L = \frac{100000\,kJ}{2\,kg}

L = 50000\,\frac{kJ}{kg}

The net calorific value of the fuel 2 is 50000 kilojoules per kilogram.

6 0
3 years ago
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