<u>First Symbol </u>: Cobalt (Co)
Its Group Number - 9
Its Period Number - 4
Its Family Name - Transition Metal
<u>Second Symbol</u> : Silicon (Si)
Its Group Number - 14
Its Period Number - 2
Its Family Name - Semiconductor
<u>Third Symbol</u> : Astatine (At)
Its Group Number - 17
Its Period Number - 6
Its Family Name - Halogen
<u>Fourth Symbol </u>: Magnesium (Mg)
Its Group Number - 2
Its Period Number - 3
Its Family Name - Alkaline Earth Metal
<u>Fifth Symbol</u> : Xenon (Xe)
Its Group Number - 18
Its Period Number - 5
Its Family Name - Noble Gas
Answer:
Explanation:
A ) angular velocity ω = 2π / T
= 2 x 3.14 / 60
= .10467 rad / s
linear velocity v = ω R
= .10467 x 50
= 5.23 m / s
centripetal force = m v² / R
= mg v² / gR
= 834 x 5.23² / 9.8 x 50
= 46.55 N
B )
apparent weight
= mg - centripetal force
= 834 - 46.55
= 787.45 N
C ) apparent weight
= mg + centripetal force
= 834 + 46.55
= 880.55 N.
D )
For apparent weight to be zero
centripetal force = mg
mg = mv² / R
v² = gR
= 9.8 x 50
= 490
v = 22.13 m /s
time period of revolution
= 2π R /v
2 x 3.14 x 50 / 22.13
= 14.19 s
Answer:
low powered radio frequency (RF) energy
Answer:
Light rain, sleet, or snow
Explanation:
pls brainlyest
Answer:
The net calorific value of the fuel 1 is 40000 kilojoules per kilogram.
The net calorific value of the fuel 2 is 50000 kilojoules per kilogram.
Explanation:
The net calorific value is equal to the heat produced (
), in kilojoules, divided by the mass of the burnt fuel (
). We proceed to calculate the net calorific value of each fuel:
Fuel 1 (
, 
)
The net calorific value of the fuel 1 is 40000 kilojoules per kilogram.
Fuel 2 (
, 
)
The net calorific value of the fuel 2 is 50000 kilojoules per kilogram.
