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2 years ago

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Which of the following could be the subshell representation of an element of Group IV?

1 answer:

Afina-wow [57]2 years ago

7 0

The subshell representation of an element of Group IV is option C. s² p², since it contains 4 valence electrons.

<h3>What are Groups?</h3>

In the Periodic Table, the Groups are the columns. For the Main-group elements, the group number coincides with the number of electrons in the valence shell.

Which of the following could be the subshell representation of an element of Group IV?

A. s². No, since there are 2 valence electrons.

B. s² p³. No, since there are 5 valence electrons.

C. s² p². Yes, since there are 4 valence electrons.

D. s² p¹. No, since there are 3 valence electrons.

The subshell representation of an element of Group IV is option C. s² p², since it contains 4 valence electrons.

Learn more about Groups here: brainly.com/question/24144303

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How does the energy required to remove an electron from an atom change as you move left to right in Period 4 from potassium through iron? ... A greater nuclear charge pulls the electrons closer to the nucleus, decreasing the atomic radius.

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2 years ago

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Naily [24]

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D) He did not multiply the chlorine and oxygen atoms by the coefficient 4.

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3 years ago

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Aluminium + copper sulfate : Why is this reaction called a displacement reaction

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3 years ago

If a recycling center collects 3245 aluminum cans and there are 22 aluminum cans in 1 lb what volume in liters

Bad White [126]

The volume in liters of 3245 aluminum cans is 24.8 L.

A recycling center collects 3245 aluminum cans and there are 22 aluminum cans in 1 lb. The mass of 3245 aluminum cans is:

$3245 cans \times \frac{1lb}{22cans} = 147.5 lb$

To convert mass to volume, we need the density of aluminum (5.95 lb/L). The volume corresponding to 147.5 lb of aluminum is:

$147.5 lb \times \frac{1L}{5.95 lb} = 24.8 L$

The volume in liters of 3245 aluminum cans is 24.8 L.

You can learn more about density here: brainly.com/question/1841285

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3 years ago

How many molecules of hydrogen gas are present in a 750 ml<br> container at STP?

BabaBlast [244]

Answer: 1.99 x 10²² molecules H2

Explanation:First we will solve for the moles of H2 using Ideal gas law PV= nRT then derive for moles ( n ).

At STP, pressure is equal to 1 atm and Temperature is 273 K.

Convert volume in mL to L:

750 mL x 1 L / 1000 mL

= 0.75 mL

n = PV/ RT

= 1 atm ( 0.75 L ) / 0.0821 L.atm/ mole.K ( 273 K)

= 3.3x10-² moles H2

Convert moles of H2 to atoms using Avogadro's Number.

3.3x10-² moles H2/ 6.022x10²³ atoms H2 / 1 mole H2

= 1.99x10²² atoms H2

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3 years ago