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2 years ago

10

Which of the following could be the subshell representation of an element of Group IV?

1 answer:

Afina-wow [57]2 years ago

7 0

The subshell representation of an element of Group IV is option C. s² p², since it contains 4 valence electrons.

<h3>What are Groups?</h3>

In the Periodic Table, the Groups are the columns. For the Main-group elements, the group number coincides with the number of electrons in the valence shell.

Which of the following could be the subshell representation of an element of Group IV?

A. s². No, since there are 2 valence electrons.

B. s² p³. No, since there are 5 valence electrons.

C. s² p². Yes, since there are 4 valence electrons.

D. s² p¹. No, since there are 3 valence electrons.

The subshell representation of an element of Group IV is option C. s² p², since it contains 4 valence electrons.

Learn more about Groups here: brainly.com/question/24144303

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6. How many moles of water would require 92.048 kJ of heat to raise its temperature from 34.0 °C to 100.0 °C? (3 marks)

scoray [572]

Taking into account the definition of calorimetry, 0.0185 moles of water are required.

<h3>Calorimetry</h3>

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

So, the equation that allows to calculate heat exchanges is:

Q = c× m× ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

<h3>Mass of water required</h3>

In this case, you know:

Heat= 92.048 kJ
Mass of water = ?
Initial temperature of water= 34 ºC
Final temperature of water= 100 ºC
Specific heat of water = 4.186 $\frac{J}{gC}$

Replacing in the expression to calculate heat exchanges:

92.048 kJ = 4.186 $\frac{J}{gC}$ × m× (100 °C -34 °C)

92.048 kJ = 4.186 $\frac{J}{gC}$ × m× 66 °C

m= 92.048 kJ ÷ (4.186 $\frac{J}{gC}$ × 66 °C)

<u><em>m= 0.333 grams</em></u>

<h3>Moles of water required</h3>

Being the molar mass of water 18 $\frac{g}{mole}$ , that is, the amount of mass that a substance contains in one mole, the moles of water required can be calculated as:

$amount of moles=0.333 gramsx\frac{1 mole}{18 grams}$

<u><em>amount of moles= 0.0185 moles</em></u>

Finally, 0.0185 moles of water are required.

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8 0

2 years ago

1. A crane lifts a 75kg mass a height of 8 m. Calculate the gravitational potential energy

koban [17]

Answer:

GP.E = 5880 j

Explanation:

Given data:

Mass = 75 kg

height = 8 m

Potential energy = ?

Solution:

The formula for gravitational potential energy is

GPE = mgh

m = mass in kilogram

g = acceleration due to gravity

h = height in meter above the ground

Formula:

GP.E = mgh

Now we will put the values in formula.

g = 9.8 m/s²

GP.E = 75 Kg × 9.8 m/s²× 8 m

GP.E = 5880 Kg.m²/s²

Kg.m²/s² = j

GP.E = 5880 j

6 0

3 years ago

PLEASE HELP!! I need to identify the substance with greatest density and explain why. I’ll give brainliest!!

madam [21]

Answer:

The blue line has the greatest desnsity

Explanation:becuase it has higher mass than any of the other ones

7 0

3 years ago

Read 2 more answers

MgO + H2O à Mg(OH)2 is an example of a _________ chemical reaction. A. synthesis B. combustion C. replacement D. decomposition

Veseljchak [2.6K]

Combustion if I aint mistaken

3 0

3 years ago

You are asked to determine the identity of an unknown liquid and can measure only one physical property. You see the liquid and

Julli [10]

The physical property you measured is the boiling point of the liquid.

Therfore, if the liquid has a boiling point of 100°C, it turns from liquid state to vapor when you heat it up to 100°C.

To conclude, The liquid should be pure water. Because only pure water has a boiling point of 100°C, using this physical property, we can test whatever liquid ans see if it's pure water or not, this test is called the boiling point test.

5 0

3 years ago