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zysi [14]
2 years ago
15

What is the equivalent resistance of a circuit that contains three 10.0 Ω

Physics
2 answers:
yanalaym [24]2 years ago
8 0

Answer:

O D.30.0 Ω

Explanation:

this <em>is </em><em>the </em><em>correct </em><em>answer</em><em>!</em>

Cerrena [4.2K]2 years ago
8 0

<u>Question</u><u> </u><u>:</u>

  • What is the equivalent resistance of a circuit that contains three 10.0 Ω resistors connected in series to a 6.0 V battery?

Options given :

  • A. 0.600 Ω
  • Β. 60.0 Ω
  • C. 16.0 Ω
  • D. 30.0 Ω

<u>Solution</u><u> </u><u>:</u>

As we know that,

When a circuit is connected in series resistance is calculated by :

  • Rs = R1 + R2 + R3 .... Rn

Here,

  • R is resistance

As a circuit contains three resistors. So R1 , R2 and R3 would be :

  • R1 = 10 Ω
  • R2 = 10 Ω
  • R3 = 10 Ω

Now,

>> Rs = 10 + 10 + 10

>> Rs = 30 Ω

Therefore,

  • Option D is correct.

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