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bixtya [17]
1 year ago
13

A ball is thrown vertically upward with an initial speed of 50 m/s. if air resistance does affect motion, then what would be its

speed upon returning to its starting point?
Physics
1 answer:
olganol [36]1 year ago
8 0

Answer:

your answer would 50 m/s I do believe

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Mr. Barcena reached a top speed of 5m/s in 2 seconds from rest, what was his average acceleration including units?
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Answer:

Explanation:

The equation for acceleration is

a=\frac{v_f-v_0}{t} where vf is the final velocity and v0 is the initial velocity. Filling in:

a=\frac{5-0}{2} so

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A boy in a wheelchair (total mass 54.5 kg) has speed 1.40 m/s at the crest of a slope 2.10 m high and 12.4 m long. At the bottom
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Answer:

630.75 j

Explanation:

from the question we have the following

total mass (m) = 54.5 kg

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final speed (Vf) = 6.6 m/s

frictional force (FF) = 41 N

height of slope (h) = 2.1 m

length of slope (d) = 12.4 m

acceleration due to gravity (g) = 9.8 m/s^2

work done (wd) = ?

  • we can calculate the work done by the boy in pushing the chair using the law of law of conservation of energy

wd + mgh = (0.5 mVf^2) - (0.5 mVi^2) + (FF x  d)

wd = (0.5 mVf^2) - (0.5 mVi^2) + (FF x  d) - (mgh)

where wd = work done

m = mass

h = height

g = acceleration due to gravity

FF = frictional force

d = distance

Vf and Vi = final and initial velocity

wd =  (0.5 x 54.5 x 6.9^2) - (0.5 x 54.5 x 1.4^2) + (41 x 12.4) - (54.5 X 9.8 X 2.1)            

wd = 630.75 j

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