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mariarad [96]
2 years ago
7

Which best describes the relationship between energy and entropy in the universe? for entropy to increase, energy must be added.

for entropy to decrease, energy must be added. for entropy to remain constant, energy must be added.
Physics
1 answer:
Gemiola [76]2 years ago
6 0

Answer:

Entropy is a measure of the order/disorder during the transformation of the state of a system and is defined as the total variation of energy at a defined temperature. From point of view of statistical mechanics, this variation of energy is generated from statistical transitions of the internal states of the system. In this sense, entropy can measure how easy it is to reach a defined state of the system. Now, imagine a text stream that arrives to you character by character in a screen. If the text is meaningless, then every character has the same probability of appearing to you and therefore the entropy is maximal because this disorder is maximal. If you want to transfer information, then you have to spend a little bit of energy in ordering the characters because this does not happen spontaneously. The final state of the system is more ordered in respect to the earlier one, so the entropy is less than the entropy of random text. This means that, if you want to reduce entropy in order to transfer information, then you must spend energy.

Explanation:

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I NEED HELP ON 2 QUESTIONS PLEASEEE
tino4ka555 [31]

Answer:

2) c) give-way vessel

3) a) With one short blast

Explanation:

2) A vessel that is required to take early substantial action to ensure avoiding  collision called Give way vessel

In overtaking, the vessel intending to overtake is the Give-Way Vessel the vessel that is going to be overtaken is the Stand-On Vessel

Therefore, the correct option is c) give-way vessel

3) When vessels use sound signals in a meeting head on situation both vessel are Give-Way vessels and both vessel pass the each other by turning to the starboard side therefore they intend to pass each other on their port side requiring one short blast

Therefore, the correct option is a) With one short blast.

4 0
3 years ago
A gasoline tank has the shape of an inverted right circular cone with base radius 4 meters and height 5 meters. Gasoline is bein
RSB [31]

Answer:

h'=0.25m/s

Explanation:

In order to solve this problem, we need to start by drawing a diagram of the given situation. (See attached image).

So, the problem talks about an inverted circular cone with a given height and radius. The problem also tells us that water is being pumped into the tank at a rate of 8m^{3}/s. As you  may see, the problem is talking about a rate of volume over time. So we need to relate the volume, with the height of the cone with its radius. This relation is found on the volume of a cone formula:

V_{cone}=\frac{1}{3} \pi r^{2}h

notie the volume formula has two unknowns or variables, so we need to relate the radius with the height with an equation we can use to rewrite our volume formula in terms of either the radius or the height. Since in this case the problem wants us to find the rate of change over time of the height of the gasoline tank, we will need to rewrite our formula in terms of the height h.

If we take a look at a cross section of the cone, we can see that we can use similar triangles to find the equation we are looking for. When using similar triangles we get:

\frac {r}{h}=\frac{4}{5}

When solving for r, we get:

r=\frac{4}{5}h

so we can substitute this into our volume of a cone formula:

V_{cone}=\frac{1}{3} \pi (\frac{4}{5}h)^{2}h

which simplifies to:

V_{cone}=\frac{1}{3} \pi (\frac{16}{25}h^{2})h

V_{cone}=\frac{16}{75} \pi h^{3}

So now we can proceed and find the partial derivative over time of each of the sides of the equation, so we get:

\frac{dV}{dt}= \frac{16}{75} \pi (3)h^{2} \frac{dh}{dt}

Which simplifies to:

\frac{dV}{dt}= \frac{16}{25} \pi h^{2} \frac{dh}{dt}

So now I can solve the equation for dh/dt (the rate of height over time, the velocity at which height is increasing)

So we get:

\frac{dh}{dt}= \frac{(dV/dt)(25)}{16 \pi h^{2}}

Now we can substitute the provided values into our equation. So we get:

\frac{dh}{dt}= \frac{(8m^{3}/s)(25)}{16 \pi (4m)^{2}}

so:

\frac{dh}{dt}=0.25m/s

3 0
3 years ago
Help immediately! Answer I need help.
garri49 [273]

Answer:

0.80 m

Explanation:

elastic potential energy formula

elastic potential energy = 0.5 × spring constant × (extension) 2

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The Cenozoic Era is best described as the era in which
zhenek [66]
The era after the KT event occurred
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3 years ago
What did Charles Darwin’s conclude on the Galapagos Island? Plz answer fast
kvasek [131]
He discovered several species of finches that varied from island to island and it helped him make his theory of natural selection.

hope this helps ! 
3 0
3 years ago
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