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Fudgin [204]
3 years ago
10

What is the periodic table of elements ​

Chemistry
2 answers:
Veronika [31]3 years ago
5 0

Answer:

\large \boxed{\mathrm{view \ explanation}}

Explanation:

The periodic table of elements is a table consisting of elements arranged by atomic number and properties. There are a total of 118 elements discovered.

sesenic [268]3 years ago
3 0

Answer:

Periodic table of element is the tabular display of chemical elements which are arranged by atomic numbers, electron configuration and recurring chemical properties

Explanation:

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It's any of the almost spherical concentric regions of matter that make up the earth and it's atmosphere, as the lithosphere and hydrosphere. 
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How many ions are there in 0.187 mol of Na+ ions
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1 mole of a substance contains 6.022x10^23 "units" of that substance.

So 0.187 mol of Na+ is 1.13x10^23 ions (6.022x10^23 x 0.187).
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gizmo_the_mogwai [7]
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PLEASE HELP
swat32

Answer:

1461.7 g of AgI

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

CaI₂ + 2AgNO₃ —> 2AgI + Ca(NO₃)₂

From the balanced equation above,

1 mole of CaI₂ reacted to produce 2 moles of AgI.

Next, we shall determine the number of mole AgI produced by the reaction of 3.11 moles of CaI₂. This can be obtained as follow:

From the balanced equation above,

1 mole of CaI₂ reacted to produce 2 moles of AgI.

Therefore, 3.11 moles of CaI₂ will react to produce = 3.11 × 2 = 6.22 moles of AgI

Finally, we shall determine the mass of 6.22 moles of AgI. This can be obtained as follow:

Mole of AgI = 6.22 moles

Molar mass of AgI = 108 + 127

= 235 g/mol

Mass of AgI =?

Mass = mole × molar mass

Mass of AgI = 6.22 × 235

Mass of AgI = 1461.7 g

Therefore, 1461.7 g of AgI were obtained from the reaction.

5 0
3 years ago
?Al + ?H2SO4 → ?Al2(SO4)3 +3H2
AfilCa [17]

The answer is: 27 grams of aluminium.

Balanced chemical reaction: 2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂.

n(H₂) = 1.5 mol; amount of hydrogen.

Form chemical reaction: n(Al) : n(H₂) = 2 : 3.

n(Al) = 2 · 1.5 mol ÷ 3.

n(Al) = 1.0 mol; amount of aluminium.

m(Al) = n(Al) · M(Al).

m(Al) = 1 mol · 27 g/mol.

m(Al) = 27 g; mass of aluminium.

5 0
3 years ago
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