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Katena32 [7]
2 years ago
13

A hot metal plate at 150°C has been placed in air at room temperature. Which event would most likely take place over the next fe

w minutes? Molecules in both the metal and the surrounding air will start moving at lower speeds. Molecules in both the metal and the surrounding air will start moving at higher speeds. The air molecules that are surrounding the metal will slow down, and the molecules in the metal will speed up. The air molecules that are surrounding the metal will speed up, and the molecules in the metal will slow down.
Chemistry
1 answer:
Inga [223]2 years ago
7 0

Answer:

The air molecules that are surrounding the metal will speed up, and the molecules in the metal will slow down.

Explanation:

As molecules heat they begin to move faster. The heat from the metal plate will make the molecules at room temperature move faster. And the room temperature makes the hot place cool, making the hot plate molecules slow down.

To visualize this, you can use this link

https://phet.colorado.edu/en/simulations/gas-properties

click the play button to activate the activity

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Cornea >iris>lens >retina

Explanation:

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A compound of copper and sulfur contains 88.39 g of metal and 44.61 g of nonmetaL How many grams of copper are in 5264 kg of com
Dahasolnce [82]

Answer :

The mass of copper in 5264 kg of compound are, 3498383.158 g

The mass of sulfur in 5264 kg of compound are, 1765616.842 g

Explanation : Given,

Mass of metal = 88.39 g

Mass of non-metal = 44.61 g

Given mass of compound = 5264 kg = 5264000 g      (1 kg = 1000 g)

Now we have to calculate the total mass of compound.

Total mass of compound = Mass of metal + Mass of non-metal

Total mass of compound = 88.39 + 44.61 = 133 g

Now we have to calculate the mass of copper.

As, 133 g of compound contains 88.39 g of copper

So, 5264000 g of compound contains \frac{5264000}{133}\times 88.39=3498383.158g of copper

The mass of copper in 5264 kg of compound are, 3498383.158 g

Now we have to calculate the mass of sulfur.

As, 133 g of compound contains 44.61 g of sulfur

So, 5264000 g of compound contains \frac{5264000}{133}\times 44.61=1765616.842g of sulfur

The mass of sulfur in 5264 kg of compound are, 1765616.842 g

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Calculate the percent of each component in the mixture. Show your calculations. Circle final answers.
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Answer:

See Explanation

Explanation:

The question is incomplete; as the mixtures are not given.

However, I'll give a general explanation on how to go about it and I'll also give an example.

The percentage of a component in a mixture is calculated as:

\%C_E = \frac{E}{T} * 100\%

Where

E = Amount of element/component

T = Amount of all elements/components

Take for instance:

In (Ca(OH)_2)

The amount of all elements is: (i.e formula mass of (Ca(OH)_2))

T = 1 * Ca + 2 * H + 2 * O

T = 1 * 40 + 2 * 1 + 2 * 16

T = 74

The amount of calcium is: (i.e formula mass of calcium)

E = 1 * Ca

E = 1 * 40

E = 40

So, the percentage component of calcium is:

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\%C_E = \frac{4000}{74}\%

\%C_E = 54.05\%

The amount of hydrogen is:

E = 2 * H

E = 2 * 1

E = 2

So, the percentage component of hydrogen is:

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\%C_E = 2.70\%

Similarly, for oxygen:

The amount of oxygen is:

E = 2 * O

E = 2 * 16

E = 32

So, the percentage component of oxygen is:

\%C_E = \frac{E}{T} * 100\%

\%C_E = \frac{32}{74} * 100\%

\%C_E = \frac{3200}{74}\%

\%C_E = 43.24\%

5 0
3 years ago
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