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Katena32 [7]
2 years ago
13

A hot metal plate at 150°C has been placed in air at room temperature. Which event would most likely take place over the next fe

w minutes? Molecules in both the metal and the surrounding air will start moving at lower speeds. Molecules in both the metal and the surrounding air will start moving at higher speeds. The air molecules that are surrounding the metal will slow down, and the molecules in the metal will speed up. The air molecules that are surrounding the metal will speed up, and the molecules in the metal will slow down.
Chemistry
1 answer:
Inga [223]2 years ago
7 0

Answer:

The air molecules that are surrounding the metal will speed up, and the molecules in the metal will slow down.

Explanation:

As molecules heat they begin to move faster. The heat from the metal plate will make the molecules at room temperature move faster. And the room temperature makes the hot place cool, making the hot plate molecules slow down.

To visualize this, you can use this link

https://phet.colorado.edu/en/simulations/gas-properties

click the play button to activate the activity

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So, if we will plot a graph between absrobance and concentration then we will obtain a straight line

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The given data is as follows.

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Hence, putting these values into the above formula we will calculate the value of slope as follows.

           Slope = \frac{\text{difference in absrobance at two points}}{\text{difference in concentrations at those points}}

                     = \frac{0.642 - 0.412}{0.475 - 0.240}

                      = \frac{0.23}{0.235}

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It is known that for the graph, line equation can be written as follows.

                       y = mx + c  ........... (1)

where,      C = intercept

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Hence, calculate the value of intercept as follows.

           0.412 = 0.24 \times 0.978 + c

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As it is given that the absorbance values 0.454 (the y-axis value). Therefore, putting this value into equation (1) we get the following.

                     y = mx + c

                  0.454 = x \times 0.978 + 0.178

                   0.276 = 0.978x

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Thus, we can conclude that the concentration of Pb in the given sample is 0.282 ppm.

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