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jek_recluse [69]
3 years ago
13

Argon has three naturally occurring isotopes: argon-36, argon-38, and argon-40. Based on argon's reported atomic mass, which iso

tope do you think is the most abundant in nature? Explain.
Chemistry
2 answers:
Sergeu [11.5K]3 years ago
5 0
Argon-40 because it is the isotope with the closest mass to the atomic mass of the element. Making it more stable than the others allowing it to be the most abundant in nature.
ivann1987 [24]3 years ago
3 0

Answer:

argon-40

Explanation:

The relative atomic mass of Argon is 39.948. This is very close to the mass of argon-40. Usually, the relative atomic mass of an element is the sum of the percentage abundance of each isotope in nature multiplied by its mass. The result of this sum is normally biased towards the isotope with the highest abundance. In the case of argon, argon-40 must have the highest abundance, hence the value of the relative atomic mass.

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Answer:

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What is the molar solubility of AgCl in a 0.050 M NaCl solution? The Ksp of AgCl is 1.6 x 10-10. (Assume that the contribution o
Hitman42 [59]

The molar solubility of AgCl:

The molar solubility of AgCl in a 0.050 M NaCl solution is 8 x 10^{-8} M Ag^{+}

What is solubility?

The solubility is the quantity of reagent required to saturate the solution or bring about the dissociation reaction's equilibrium.

Reaction:

The dissociation reaction of AgCl in water is:

AgCl  ⇄ Ag^{+} + Cl^{-}

Each mole of AgCl that dissolves in this reaction yields 1 mole of both Ag^{+} and  Cl^{-}. The concentration of either the Ag or Cl ions would then be equal to the solubility.

Solubility= [Ag^{+}] = [Cl^{-}]

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in 0.050 M NaCl, the [Cl^{-}] = 1 x 10^{-2}

ksp = [Ag^{+}] x [Cl^{-}]

1.6 x 10^{-10} = [Ag{+}] x ( 5 x 10^{-2})

[Ag^{+}] = 5 x 10^{+2} x 1.6 x 10^{-10}

[Ag^{+}] = 5 x 1.6 x 10^{-10+2}

[Ag^{+}] = 8 x 10^{-8} M

Learn more about molar solubility here,

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