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Basile [38]
4 years ago
5

A current carrying loop of wire lies flat on a table top. When viewed from above, the current moves around the loop in a counter

clockwise sense.
(a) For points OUTSIDE the loop, the magnetic field caused by this current:________.
a. points straight up.
b. circles the loop in a clockwise direction.
c. circles the loop in a counterclockwise direction.
d. points straight down.
e. is zero.
(b) For points INSIDE the loop, the magnetic field caused by this current:________.
a. circles the loop in a counterclockwise direction.
b. points straight up.
c. points straight down.
d. circles the loop in a clockwise direction.
e. is zero
Physics
1 answer:
lora16 [44]4 years ago
5 0

Answer:

D &B

Explanation:

Using Fleming right hand rule that States that if the fore-finger, middle finger and the thumb of left hand are stretched mutually perpendicular to each other, such that fore-finger points in the direction of magnetic field, the middle finger points in the direction of the motion of positive charge, then the thumb points to the direction of the force

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Murrr4er [49]

Answer:

70.7m/s

Explanation:

V =     ( v + u)

          _____

               2

V = average velocity

v = final velocity

u = initial velocity

velocity = distance

                 ______

                   time

u (initial velocity)   = 33 ÷  2

change mins to seconds

1 min = 60 secs

2 mins =  ?

cross multiply

60 × 2 = 120 secs

u = 33 ÷ 120

u = 0.275m/s

v ( final velocity) = 29 ÷ 1.3

change mins to secs

1 min = 60 secs

1.3 mins = ?

cross multiply

1.3 × 60 = 78 secs

v = 29 ÷ 78

v = 0.371 m/s

V =  ( v + u )

       _____

           2

V =    ( 0.371 + 0.275)

         ____________

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V  =   0.51 m/s

                           

5 0
3 years ago
Help please!!!!!!!!!!!!
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7 0
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The comet-hunting astronomer who made a list of over 100 nebulae and galaxies that could be mistaken for comets was Group of ans
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An Astronomer who made a list of 100 nebulae and galaxies that could

be mistaken for comets was Charles Messer's.

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5 0
2 years ago
Fermi energy of conduction electrons in silver is 0.548 J. Calculate the number of such electrons in unit cm3
ICE Princess25 [194]

Answer:

n=1.86*10^{-30}m^3

Explanation:

From the question we are told that:

Fermi energy of conduction electrons E_f=0.548J

Generally the equation for Fermi energy is mathematically given by

 E_f=\frac{3}{\pi}^2/3*\frac{h^2}{8m}*{n^{2/3}}

 E_f=\frac{3}{\pi}^2/3*\frac{h^2}{8m}*{n^{2/3}}

 {n^{2/3}}=\frac{E_f}{\frac{3}{\pi}^2/3*\frac{h^2}{8m}}

Where

h= Planck's constant

 {n^{2/3}}=\frac{E_f}{\frac{3}{\pi}^2/3*\frac{h^2}{8m}}

 {n^{2/3}}=\frac{0.548J}{3.62*10^{-19}}

 n=(1.51*10^{-20})^{3/2}

 n=1.86*10^{-30}m^3

3 0
3 years ago
Find the time t2 that it would take the charge of the capacitor to reach 99.99% of its maximum value given that r=12.0ω and c=50
defon

Answer:

Explanation:

Given that, .

R = 12 ohms

C = 500μf.

Time t =? When the charge reaches 99.99% of maximum

The charge on a RC circuit is given as

A discharging circuit

Q = Qo•exp(-t/RC)

Where RC is the time constant

τ = RC = 12 × 500 ×10^-6

τ = 0.006 sec

The maximum charge is Qo,

Therefore Q = 99.99% of Qo

Then, Q = 99.99/100 × Qo

Q = 0.9999Qo

So, substituting this into the equation above

Q = Qo•exp(-t/RC)

0.9999Qo = Qo•exp(-t / 0.006)

Divide both side by Qo

0.9999 = exp(-t / 0.006)

Take In of both sodes

In(0.9999) = In(exp(-t / 0.006))

-1 × 10^-4 = -t / 0.006

t = -1 × 10^-4 × - 0.006

t = 6 × 10^-7 second

So it will take 6 × 10^-7 a for charge to reached 99.99% of it's maximum charge

8 0
3 years ago
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