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2 years ago

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6. A student travels 4.0 m east, 8.0 m south, 4.0 m west, and finally 8.0 m north. What is her

1 answer:

Helen [10]2 years ago

3 0

The student's path traces out a rectangle and she ends up at the same spot, so her <u>displacement</u> is 0 m.

On the other hand, she travels a <u>total distance</u> equal to the perimeter of that rectangle,

4.0 m + 8.0 m + 4.0 m + 8.0 m = 24 m

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frosja888 [35]

Answer:t=0.3253 s

Explanation:

Given

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Suppose after t sec of throw camera reach balloon then,

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and distance travel by camera to reach balloon is

$s_1=ut+\frac{1}{2}at^2$

$s_1=20\times t-\frac{1}{2}gt^2$

Now

$\Rightarrow s_1=5+s$

$\Rightarrow 20\times t-\frac{1}{2}gt^2 =5+3t$

$\Rightarrow 5t^2-17t+5=0$

$\Rightarrow t=\dfrac{17\pm \sqrt{17^2-4(5)(5)}}{2\times 5}$

$\Rightarrow t=\dfrac{17\pm 13.747}{10}$

$\Rightarrow t=0.3253\ s\ \text{and}\ t=3.07\ s$

There are two times when camera reaches the same level as balloon and the smaller time is associated with with the first one .

(b)When passenger catches the camera time is $t=0.3253\ s$

velocity is given by

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$v=20-10\times 0.3253$

$v=16.747\ m/s$

and position of camera is same as of balloon so

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Answer:

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