Answer:
Molarity of solution = 0.9 M
Explanation:
Given data:
Moles of ZnCl₂ = 4.50 mol
Volume of solution = 200 mL
Molarity of solution = ?
Solution:
Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.
Formula:
Molarity = number of moles of solute / L of solution
Now we will convert the volume in L.
200 mL×1 L/1000 mL = 0.2L
M = 4.50 mol / 0.2 L
M = 0.9 M
I thought about writing it for you but then i found this and thought i will give help but at the sometime allow you write the response you self
You need to calculate the molar mass for Al(CN)3 using the atomic weights for Al, C, and N given on the periodic table.
1 Al (26.98) + 3 C (3 x 12.01) + 3 N (3 x 14.01) = 105.04 g Al(CN)3 / mole
183 g Al(CN)3 x (1 mole Al(CN)3 / 105.04 g Al(CN)3) = 1.74 moles Al(CN)3
Answer:
Weathering (breaking down rock) and erosion (transporting rock material) at or near the earth's surface breaks down rocks into small and smaller pieces. ... If the newly formed metamorphic rock continues to heat, it can eventually melt and become molten (magma).
Explanation:
NOT MY WORDS! I HOPE THIS HELPS THO!
Answer:
This metal has a specific heat of 0.9845J/ g °C
Explanation:
Step 1: Given data
q = m*ΔT *Cp
⇒with m = mass of the substance
⇒with ΔT = change in temp = final temperature T2 - initial temperature T1
⇒with Cp = specific heat (Cpwater = 4.184J/g °C) (Cpmetam = TO BE DETERMINED)
Step 2: Calculate specific heat
For this situation : we get for q = m*ΔT *Cp
q(lost, metal) = q(gained, water)
- mass of metal(ΔT)(Cpmetal) = mass of water (ΔT) (Cpwater)
-5 * (15-100)(Cpmetal) = 20* (15-10) * (4.184J/g °C =
-5 * (-85)(Cpmetal) = 418.4
Cpmetal = 418.4 / (-5*-85) = 0.9845 J/g °C
This metal has a specific heat of 0.9845J/ g °C