1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Softa [21]
3 years ago
14

What is the maximum power that can be delivered by a 1.4-cm-diameter laser beam propagating through air

Physics
1 answer:
Aleksandr-060686 [28]3 years ago
5 0

Complete Question

The maximum electric field strength in air is 4.0 MV/m. Stronger electric fields ionize the air and create a spark. What is the maximum power that can be delivered by a 1.4-cm-diameter laser beam propagating through air

Answer:

The  value  is  P = 3.270960 *10^{6} \  W

Explanation:

From the question we are told that

   The  electric field strength is  E  = 4.0 \  M \  V/m  =  4.0 *10^6 \  V/m

    The  diameter is  d =  1.4 \  cm  = 0.014 \ m

Generally the radius is mathematically represented as

        r = \frac{d}{2}

=>     r = \frac{0.014}{2}

=>    r   = 0.007 \  m

Generally the cross-sectional area is mathematically represented as

        A =  \pi r^2

        A =  3.142 *  (0.007)^2

       A = 0.000154 \ m^2

Generally the maximum power that can be delivered is mathematically represented as

        P = \frac{c *  \epsilon_o  *  E^2 *  A }{2}

Here c is the speed of light with value  c =  3.0*10^{8} \  m/s

        \epsilon_o is the permittivity of free space with value  \epsilon_o  =  8.85 *10^{-12}  \ m^{-3} \cdot kg^{-1}\cdot  s^4 \cdot A^2

     P =  \frac{3,0*10^8 *  8.85*10^{-12} *  (4 *10^6)^2 * 0.00154}{ 2}

       P = 3.270960 *10^{6} \  W

         

You might be interested in
During a physical science lab investigating chemical reactions, several students placed a 30g antacid tablet in a 30g zip-lock b
ICE Princess25 [194]
30 Grams would be your answer (I took the test and got it right)
8 0
3 years ago
Read 2 more answers
What is the force of gravity between two 40.0kg masses that are separated by 3.00m?
Slav-nsk [51]

Answer:

f = g \times \frac{m1 \times m2}{ {d}^{2} }

f = 6.67 \times  {10}^{ - 11}  \times \frac{40 \times 40}{9}

<h2>F=1.2x 10^-8</h2>
3 0
3 years ago
Which quantity is a vector quantity? displacement<br> distance<br> mass<br> temperature<br> volume
Arturiano [62]
The only vector quantity on that list is displacement.
8 0
3 years ago
Read 2 more answers
which one of these represent total momentum of a system of two particles traveling one against the other?
antoniya [11.8K]

The total momentum of a system is the vector sum of all the individual masses that comprise the system.

Moreover, To calculate the total momentum of two objects during a collision, add their individual momentums. You can calculate the momentum for each object using the formula p=mv, where p is the momentum, m is the mass, and v is the velocity. The law of conservation of momentum can be expressed as follows. For a collision between object 1 and object 2 in an isolated system, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.

You can learn more about this at:

brainly.com/question/20301772#SPJ4

5 0
1 year ago
A capacitance C and an inductance L are operated at the same angular frequency.
Levart [38]

A) \omega = \frac{1}{\sqrt{LC}}

The magnitude of the capacitive reactance is given by

X_C = \frac{1}{\omega C}

where

\omega is the angular frequency

C is the capacitance

While the magnitude of the inductive capacitance is given by

X_L = \omega L

where L is the inductance.

Since we want the two reactances to be equal, we have

X_C = X_L

So we find

\frac{1}{\omega C}= \omega L\\\omega^2 = \frac{1}{LC}\\\omega = \frac{1}{\sqrt{LC}}

B) 7449 rad/s

In this case, we have

L=5.30 mH = 5.3\cdot 10^{-3}H is the inductance

C= 3.40 \mu F= 3.40 \cdot 10^{-6}F is the capacitance

Therefore, substituting in the formula for the angular frequency, we find

\omega=\frac{1}{\sqrt{LC}}=\frac{1}{\sqrt{(5.30\cdot 10^{-3}H)(3.40\cdot 10^{-6} F)}}=7449 rad/s

C) 39.5 \Omega

Now we can us the formulas of the reactances written in part A). We have:

- Capacitive reactance:

X_C = \frac{1}{\omega C}=\frac{1}{(7449 rad/s)(3.40\cdot 10^{-6}F)}=39.5 \Omega

- Inductive reactance:

X_L = \omega L=(7449 rad/s)(5.30\cdot 10^{-3}H)=39.5 \Omega

7 0
3 years ago
Other questions:
  • If an atom had 35 protons in the nucleus how many electrons will it have orbiting the nucleus ?
    10·2 answers
  • If different groups of scientist have access to the same data, how can they draw different conclusions?
    5·1 answer
  • Why do smaller endotherms require more energy per unit of mass than larger endotherms?
    12·1 answer
  • Determine the critical crack length for a through crack contained within a thick plate of 7150-T651 aluminum alloy that is in un
    9·1 answer
  • Ethical behavior by therapists is important because
    11·2 answers
  • A flywheel in a motor is spinning at 590 rpm when a power failure suddenly occurs. The flywheel has mass 40.0 kg and diameter 75
    14·1 answer
  • 4. Look at the graph above. What information is on the graph and what does it mean? Please help!!!
    6·1 answer
  • Can someone plz answere my question<br> for science
    9·1 answer
  • A 6 cm object is 8 cm from a convex lens that has a focal length of 2.7 cm. The image is 4 cm from the lens.
    6·2 answers
  • What are the equivalent celsius and kelvin temperatures of -128 f?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!