Answer:
Option B, visual sightings
Explanation:
Options for the question are
A) accountability mechanism
B) visual sightings
C) intelligence
D) surveillance
E) reconnaissance operations, or communications
Solutions
The Fundamentals of Army Personnel Recovery (PR) outlines certain circumstances under which a person has to undergo survival situation thereby taking the necessary steps to avoid capture and return safely to their respective unit.
An isolated soldier is expected to know where they are, upcoming route and rally points. They are supposed to know the near and far recognition signals, recovery site protocols, challenge and password etc. A proper preparation is to be done for this including planning, medicines, kits, etc.
Visual sightings is not an essential part of isolated PR
Hence, option B is correct
Answer:
Acceleration, 
Explanation:
Given that,
Mass of the planet Krypton, 
Radius of the planet Krypton, 
Value of gravitational constant, 
To find,
The acceleration of an object in free fall near the surface of Krypton.
Solution,
The relation for the acceleration of the object is given by the below formula as :
So, the value of acceleration of an object in free fall near the surface of Krypton is 
41.2 = h-1/2g(t-1)^2
<span> {-h = -1/2gt^2-1/2g+g*t-41.2
</span><span> {h = 1/2gt^2
</span><span> summing them up
</span><span> 0 = -1/2g+g*t-41.2
</span><span> 41.2 +4.9 = g*t
</span><span> t = 46.1/9.8 = 4.70 sec
</span><span> h = 1/2gt^2 =4.9*(4.70^2) = 108.241 m </span>
Answer:
he angular velocity w = 4.19 rad / s
Explanation:
The girl is synchronized with the movement of the rope, therefore we can describe the movement of the girl with the angular velocity
w = θ/t
if we fear 40 jumps and each one is a revolution
θ = 40 2pi = 80π radiation
t = 1 min = 60 s
w = 80π / 60
w = 4.19 rad / s
this must be the same angular velocity of the rope
Answer:
The coin comes to rest after covering 1.023 m.
Explanation:
initial angular speed, wo = 18 rad/s
final angular speed, w = 0 rad/s
angular acceleration, = 1.9 rad/s2
radius, r = 1.2 cm = 0.012 m
initial linear velocity, u = r wo = 0.012 x 18 = 0.216 m/s
final linear speed, v = r w = 0.012 x 0 = 0 m/s
linear acceleration, a = r x angular acceleration = 0.012 x 1.9 = 0.0228 m/s2
let the distance traveled is s.
Use third equation of motion
