Question

Calculate the mole fraction of each component in a solution of 42 g CH3OH, 35 g of chloroform CHCl3, and 50 g C3H7OH

Answer 1

Considering the definition of mole fraction, the mole fraction of each component in the solution is:

• CH₃OH: 0.54
• CHCl₃: 0.118
• C₃H₇OH: 0.342

Mole fraction

The molar fraction is a way of measuring the concentration that expresses the proportion in which a substance is found with respect to the total moles of the solution.

Mole fraction of each component

In this case, in first place you should know that the molar mass of each component is:

• CH₃OH: 32 $\frac{g}{mole}$
• CHCl₃: 121.35 $\frac{g}{mole}$
• C₃H₇OH: 60 $\frac{g}{mole}$

Now, the number of moles of each compound can be calculated as:

• CH₃OH: $\frac{42 g}{32\frac{g}{mole}}$=  1.3125 moles
• CHCl₃: $\frac{35 g}{121.35\frac{g}{mole}}$= 0.2884 moles
• C₃H₇OH: $\frac{50 g}{60\frac{g}{mole}}$=  0.8333 moles

So, the total moles of the solution can be calculated as:

Total moles = 1.3125 moles + 0.2884 moles + 0.8333 moles

Total moles = 2.4342 moles

Finally, the more fraction of each component can be calculated as follow:

• CH₃OH: $\frac{1.3125 moles}{2.4342 moles}$= 0.54
• CHCl₃: $\frac{0.2884 moles}{2.4342 moles}$= 0.118
• C₃H₇OH: $\frac{0.8333 moles}{2.4342 moles}$= 0.342

In summary, the mole fraction of each component in the solution is:

• CH₃OH: 0.54
• CHCl₃: 0.118
• C₃H₇OH: 0.342

Learn more about mole fraction:

brainly.com/question/14434096

brainly.com/question/10095502

#SPJ1