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aalyn [17]
2 years ago
5

Higher-pitched sounds have shorter wavelengths. True or false

Physics
2 answers:
mariarad [96]2 years ago
7 0

Answer:

it's true

Explanation:

High–pitched sounds have short wavelengths, which means that the peaks are close together. Low–pitched sounds have longer wavelengths, so the peaks are more spread out.

Eva8 [605]2 years ago
5 0

Answer:

The answer is True

Explanation:

I hope it helps

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Roberto makes a graphic organizer to compare fusion nuclear reactions and fission nuclear reactions. A venn diagram with 2 inter
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The second one

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The second one is joining so it is the one which belongs to X, first one belongs to Z

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3 years ago
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However, when is the best time to fill a balloon? Helium has a tendency to escape from any opening in the balloon and will event
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2 years ago
What inertia is present in a stretched rubber?​
iVinArrow [24]

Answer:

You input potential energy into the rubber band system when you stretched the rubber band back. Because it is an elastic system, this is kind of potential energy is specifically called elastic potential energy.

7 0
3 years ago
What is the sound intensity level in a car when the sound intensity is 0.525 μW/m2 ? Use I0 = 1.00×10−12 W/m2 for the reference
never [62]

Answer:

The sound intensity level in the car is 57.2 dB.

Explanation:

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Hope this Helps!!!

8 0
3 years ago
A head-on, elastic collision between two particles with equal initial speed v leaves the more massive particle (mass m1) at rest
ZanzabumX [31]
<span>1/3 The key thing to remember about an elastic collision is that it preserves both momentum and kinetic energy. For this problem I will assume the more massive particle has a mass of 1 and that the initial velocities are 1 and -1. The ratio of the masses will be represented by the less massive particle and will have the value "r" The equation for kinetic energy is E = 1/2MV^2. So the energy for the system prior to collision is 0.5r(-1)^2 + 0.5(1)^2 = 0.5r + 0.5 The energy after the collision is 0.5rv^2 Setting the two equations equal to each other 0.5r + 0.5 = 0.5rv^2 r + 1 = rv^2 (r + 1)/r = v^2 sqrt((r + 1)/r) = v The momentum prior to collision is -1r + 1 Momentum after collision is rv Setting the equations equal to each other rv = -1r + 1 rv +1r = 1 r(v+1) = 1 Now we have 2 equations with 2 unknowns. sqrt((r + 1)/r) = v r(v+1) = 1 Substitute the value v in the 2nd equation with sqrt((r+1)/r) and solve for r. r(sqrt((r + 1)/r)+1) = 1 r*sqrt((r + 1)/r) + r = 1 r*sqrt(1+1/r) + r = 1 r*sqrt(1+1/r) = 1 - r r^2*(1+1/r) = 1 - 2r + r^2 r^2 + r = 1 - 2r + r^2 r = 1 - 2r 3r = 1 r = 1/3 So the less massive particle is 1/3 the mass of the more massive particle.</span>
8 0
3 years ago
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