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Stels [109]
1 year ago
7

Increasing the airplane's speed or wing size does which of the following

Chemistry
1 answer:
mariarad [96]1 year ago
6 0

Answer:

increases the gravitional pull on tge pane

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TRUE FALSE? The MOLE is a unit in Chemistry that serves as a bridge between the ATOMIC and MACROSCOPIC worlds?​
Vanyuwa [196]

Answer:

True

Explanation:

A mole is defined as 6.02214076 × 1023 of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

7 0
3 years ago
Read 2 more answers
How can a piece of wood floating on water illustrate the condition of lowest potential energy and maximum
drek231 [11]

Answer:

By minimizing the height of the body's center of gravity relative to its center of buoyancy

Explanation:

In hydrostatics, the equilibrium state of a floating body relates to either a maximum or minimum of the potential energy.An equilibrium is stable when the potential energy is minimum.Minimizing the height of the floating body's center of gravity relative to its center of buoyancy attains a stable equilibrium configuration.

4 0
3 years ago
HELP......Percussion instruments are musical instruments that make noise when they are hit with an object. Which of these are pe
valkas [14]

Answer:

I believe that the percussion instruments are the drum and cymbal.

Explanation:

4 0
3 years ago
Can u help me with this
dolphi86 [110]

Answer:

c

Explanation:

the reason is because your a homosiejenenddj

8 0
2 years ago
Be sure to answer all parts. calculate δg ocell for the reaction between cr(s) and cu2+(aq). e ocell = 1.08 j/c. enter your answ
Mademuasel [1]

Answer:

\boxed{-6.29 \times10^{5}\text{ J}}

Explanation:

Step 1. Determine the cell potential

                                                  <u>    E°/V     </u>

2×[Cr ⟶ Cr³⁺ + 3e⁻]                  0.744  V

<u>3×[Cu²⁺ + 2e⁻ ⟶ Cu]             </u>   <u>0.3419 V </u>

2Cr + 3Cu²⁺ ⟶ 3Cu  + 2Cr³⁺    1.086  V

Step 2. Calculate ΔG°

\Delta G^{\circ} = -nFE_{\text{cell}}^{^{\circ}} = -6 \times 96 485 \times 1.086 = \text{-629 000 J}\\\\= \boxed{-6.29 \times10^{5}\text{ J}}

6 0
3 years ago
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