If the rate of infusion

The reaction between bromine gas and fluorine gas to create bromine monofluoride gas has reached equilibrium. what is the effect

WITCHER [35]

More bromine gas will be produced.

5 0

3 years ago

A protein is Select one: a. a saturated ester of glycerol. b. a polysaccharide. c. an aromatic hydrocarbon. d. a polymer of amin

Rzqust [24]

Answer:

D

Explanation:

The building blocks or monomers of proteins are called amino acids. There are 20 different kinds of amino acids. The amino acids form long chains that are proteins. Therefore, proteins are polymers of amino acids.

Proteins are very important for the body because they have many different roles. They provide structure for tissues, act as enzymes, hormones and antibodies, aid in transportation and fluid regulation.

Therefore, the correct answer is D. a polymer of amino acids.

7 0

3 years ago

Pls help mee with this

Whitepunk [10]

Answer:

C. Shield Volcano

Explanation:

Flow after flow pours out in all directions from a central summit vent, or group of vents, building a broad, gently sloping cone of flat, domical shape, with a profile much like that of a warrior's shield.

4 0

2 years ago

Consider the reaction N2(g) + 2O2(g)2NO2(g) Using standard thermodynamic data at 298K, calculate the entropy change for the surr

zysi [14]

Answer: The value of $\Delta S^o$ for the surrounding when given amount of nitrogen gas is reacted is 231.36 J/K

Explanation:

Entropy change is defined as the difference in entropy of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate entropy change is of a reaction is:

$\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{(product)}]-\sum [n\times \Delta S^o_{(reactant)}]$

For the given chemical reaction:

$N_2+2O_2\rightarrow 2NO_2$

The equation for the entropy change of the above reaction is:

$\Delta S^o_{rxn}=[(2\times \Delta S^o_{(NO_2(g))})]-[(1\times \Delta S^o_{(N_2(g))})+(2\times \Delta S^o_{(O_2(g))})]$

We are given:

$\Delta S^o_{(NO_2(g))}=240.06J/K.mol\\\Delta S^o_{(O_2)}=205.14J/K.mol\\\Delta S^o_{(N_2)}=191.61J/K.mol$

Putting values in above equation, we get:

$\Delta S^o_{rxn}=[(2\times (240.06))]-[(1\times (191.61))+(2\times (205.14))]\\\\\Delta S^o_{rxn}=-121.77J/K$

Entropy change of the surrounding = - (Entropy change of the system) = -(-121.77) J/K = 121.77 J/K

We are given:

Moles of nitrogen gas reacted = 1.90 moles

By Stoichiometry of the reaction:

When 1 mole of nitrogen gas is reacted, the entropy change of the surrounding will be 121.77 J/K

So, when 1.90 moles of nitrogen gas is reacted, the entropy change of the surrounding will be = $\frac{121.77}{1}\times 1.90=231.36 J/K$

Hence, the value of $\Delta S^o$ for the surrounding when given amount of nitrogen gas is reacted is 231.36 J/K

7 0

3 years ago

A weak acid, ha, has a p��a of 4. 524. If a solution of this acid has a ph of 4. 799 , what percentage of the acid is not io

insens350 [35]

Answer:

highly endothermic

Explanation:

6 0

2 years ago

If the rate of infusion​

If the rate of infusion