Mass of KCl= 19.57 g
<h3>Further explanation</h3>
Given
12.6 g of Oxygen
Required
mass of KCl
Solution
Reaction
2KClO3 ⇒ 2KCl + 3O2
mol O2 :
= mass : MW
= 12.6 : 32 g/mol
= 0.39375
From the equation, mol KCl :
= 2/3 x mol O2
= 2/3 x 0.39375
=0.2625
Mass KCl :
= mol x MW
= 0.2625 x 74,5513 g/mol
= 19.57 g
Answer:most of the positively charge particles should be bounce back at a range of angles as they collide with the atoms in the foil; only a few should pass straight through the foil
Explanation:
I’d say for the answer 13.13 mmHg?
Answer:
C8H18(g) + 12.5O2(g) -> __8__CO2(g) + 9H2O(g) + heat
CH4(g) + _2___O2(g) -> ____CO2(g) + _2___H2O(g) + heat
C3H8(g) + _5___O2(g) -> _3___CO2(g) + __4__H2O(g) + heat
2C6H6(g) + __15__O2(g) -> __12__CO2(g) + __6__H2O(g) + heat
Explanation:
I hope it helps!
