Answer: Option (B) is the correct answer.
Explanation:
Expression for the given decomposition reaction is as follows.
Let us assume that x concentration of 
is present at the initial stage. Therefore, according to the ICE table,
Initial : x 0
Change : - 0.1 
Equilibrium : (x - 0.1) 0.2
Now, expression for 
of this reaction is as follows.
Putting the given values into the above formula as follows.
x = 0.12
This means that 
= x = 0.12 atm.
Thus, we can conclude that the initial pressure in the container prior to decomposition is 0.12 atm.
Answer:
The molarity (M) of the following solutions are :
A. M = 0.88 M
B. M = 0.76 M
Explanation:
A. Molarity (M) of 19.2 g of Al(OH)3 dissolved in water to make 280 mL of solution.
Molar mass of Al(OH)3 = Mass of Al + 3(mass of O + mass of H)
= 27 + 3(16 + 1)
= 27 + 3(17) = 27 + 51
= 78 g/mole
= 78 g/mole
Given mass= 19.2 g/mole
Moles = 0.246
Volume = 280 mL = 0.280 L
Molarity = 0.879 M
Molarity = 0.88 M
B .The molarity (M) of a 2.6 L solution made with 235.9 g of KBr
Molar mass of KBr = 119 g/mole
Given mass = 235.9 g
Moles = 1.98
Volume = 2.6 L
Molarity = 0.762 M
Molarity = 0.76 M
I don't know sorry I really need point
2) Should be tested by the scientific community
