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Darina [25.2K]
2 years ago
7

It requires 334 kJ of heat to melt 1 kg of ice. The largest known iceberg had a volume of about 3.1 x 1013 m³. How much heat was

required
to melt the iceberg if 1 m³ of ice has a mass of 917 kg?
Chemistry
1 answer:
umka21 [38]2 years ago
8 0

The  amount of heat required to melt the iceberg at 9.58 * 10¹⁸ kJ.

<h3>What is the amount of heat required to melt an iceberg that has a volume of about 3.1 x 1013 m³?</h3>

The heat required to melt a unit mass of ice is known as the latent heat of fusion.

The latent heat of fusion of ice of 1 kg= 334 kJ of heat

Mass of iceberg = 3.1 x 10¹³ m³ * 917 kg = 2.8427 * 10¹⁶ kg

Amount of heat required = 2.8427 * 10¹⁶ * 334 = 9.58 * 10¹⁸ kJ.

Therefore, the amount of heat required to melt the iceberg at 9.58 * 10¹⁸ kJ.

Learn more about latent heat of fusion at: brainly.com/question/87248

#SPJ1

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A gamma ray photon has an energy of 4.75 x 10-14 joules. What is the frequency of this radiation?
Rama09 [41]

The frequency of the radiation is equal to 7.17  \times 10^{19} Hertz.

<u>Given the following data:</u>

  • Photon energy = 4.75 \times 10^{-14} Joules

To find the frequency of this radiation, we would use the Planck-Einstein equation.

Mathematically, the Planck-Einstein relation is given by the formula:

E = hf

<u>Where:</u>

  • h is Planck constant.
  • f is photon frequency.

Substituting the given parameters into the formula, we have;

4.75 \times 10^{-14} = 6.626 \times 10^{-34} \times F\\\\F = \frac{4.75 \times 10^{-14}}{6.626 \times 10^{-34}}

Frequency, F = 7.17  \times 10^{19} Hertz

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4 0
2 years ago
What is 254 K in degrees Celsius. Show all work and include units for full credit.
kondor19780726 [428]
-19.15 degrees Celsius. 254k-273.15=-19.15
You have to subtract 273
6 0
2 years ago
A 2.87 g sample of carbon reacts with hydrogen to form 3.41 g of car fuel. What is the empirical formula for the car fuel?
olga_2 [115]

CH₇ is the empirical formula of the car fuel.

Explanation:

To find the empirical formula we use the following algorithm.

First divide each mass the the molar weight of each element:

for carbon 2.87 / 12 = 0.239

for hydrogen 3.41 / 2 = 1.705

And now divide each quantity by the lowest number which is 0.239:

for carbon 0.239 / 0.239 = 1

for hydrogen 1.705 / 0.239 = 7.13 ≈ 7

The empirical formula of the car fuel is CH₇.

I have to tell you that in reality this formula is wrong because is not possible to exist. However the algorithm for finding the empirical formula is right, the problem may reside in the amounts of carbon and hydrogen given.

Learn more about:

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is there supposed be a picture with the question?


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Where two air masses and do not mix
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When two air masses meet together, the boundary between the two is called a weather front. At a front, the two air masses have different densities, based on temperature, and do not easily mix. One air mass is lifted above the other, creating a low pressure zone.
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