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velikii [3]
2 years ago
8

50 atoms, 15 were isotope A, 30 were isotope B, and 5 were isotope C, which isotope would be the most abundant?

Chemistry
1 answer:
Juliette [100K]2 years ago
5 0

The most abundant isotope among the given Isotopes will be Isotope B

<h3>How to calculate percentage abundance of isotopes ?</h3>

To calculate the percent abundance of each isotope in a sample of an element, we usually divide the number of atoms of a particular isotope by the total number of atoms of all isotopes of that element and then multiply the result by 100.

  • For  Isotope A ;

% Abundance =  15/50 x 100

                        =  30 %

  • For  Isotope B ;

% Abundance =  30/50 x 100

                        =  60 %

  • For  Isotope A ;

% Abundance =  5/50 x 100

                        =  10 %

Hence, The most abundant isotope among the given Isotopes will be Isotope B.

Learn more about isotopes here ;

brainly.com/question/12955625

#SPJ1

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Given the two reactions PbCl2(aq)⇌Pb2+(aq)+2Cl−(aq), K3 = 1.84×10−10, and AgCl(aq)⇌Ag+(aq)+Cl−(aq), K4 = 1.14×10−4, what is the
Nimfa-mama [501]

Answer: The value of equilibrium constant for reaction is, 1.42\times 10^{-2}

Explanation:

The given chemical equations are:

(1) PbCl_2(aq)\rightleftharpoons Pb^{2+}(aq)+2Cl^-(aq) ;  K_3=1.84\times 10^{-10}

(2) AgCl(aq)\rightleftharpoons Ag^{+}(aq)+Cl^-(aq) ;  K_4=1.14\times 10^{-4}

Now we have to calculate the equilibrium constant for chemical equation as:

PbCl_2(aq)+2Ag^{+}(aq)\rightleftharpoons 2AgCl(aq)+Pb^{2+}(aq) ;  K=?

We are reversing reaction 2 and multiplying reaction 2 by 2 and then adding both reaction, we get the final reaction.

The equilibrium constant for the reverse reaction will be the reciprocal of that reaction.

If the equation is multiplied by a factor of '2', the equilibrium constant of that reaction will be the square of the equilibrium constant.

If we are adding equations then the equilibrium constants will be multiplied.

The value of equilibrium constant for reaction is:

K=(\frac{1}{K_4})^2\times K_3

Now put all the given values in this expression, we get:

K=(\frac{1}{1.14\times 10^{-4}})^2\times (1.84\times 10^{-10})

K=1.42\times 10^{-2}

Hence, the value of equilibrium constant for reaction is, 1.42\times 10^{-2}

7 0
4 years ago
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Answer:

A

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The molecules in both metal and surrounding air will start moving slower because of the sudden decrease in environment tmeperature. The thermal energy around the metal plate decreases, also decreasing the kinetic energy.

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