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velikii [3]
2 years ago
8

50 atoms, 15 were isotope A, 30 were isotope B, and 5 were isotope C, which isotope would be the most abundant?

Chemistry
1 answer:
Juliette [100K]2 years ago
5 0

The most abundant isotope among the given Isotopes will be Isotope B

<h3>How to calculate percentage abundance of isotopes ?</h3>

To calculate the percent abundance of each isotope in a sample of an element, we usually divide the number of atoms of a particular isotope by the total number of atoms of all isotopes of that element and then multiply the result by 100.

  • For  Isotope A ;

% Abundance =  15/50 x 100

                        =  30 %

  • For  Isotope B ;

% Abundance =  30/50 x 100

                        =  60 %

  • For  Isotope A ;

% Abundance =  5/50 x 100

                        =  10 %

Hence, The most abundant isotope among the given Isotopes will be Isotope B.

Learn more about isotopes here ;

brainly.com/question/12955625

#SPJ1

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The compound cisplatin, pt(nh3)2cl2 , has been studied extensively as an antitumor agent.
Nataliya [291]

a. Elemental percent composition is the mass percent of each element in the compound.

The formula for mass elemental percent composition = \frac{mass of element}{mass of compound}   (1)

The molecular formula of cisplatin is Pt(NH_3)_2Cl_2.

The atomic weight of the elements in cisplatin is:

Platinum, Pt = 195.084 u

Nitrogen, N = 14.0067 u

Hydrogen, H = 1 u

Chlorine, Cl = 35.453 u

The molar mass of Pt(NH_3)_2Cl_2 = 195.084+ (2\times 14.0067)+(6\times 1)+(2\times 35.453) = 300.00 g/mol

The mass of each element calculated using formula (1):

- Platinum, Pt %

\frac{195.084}{300.00} \times 100 = 65.23%.

- Nitrogen, N%

\frac{2\times 14.0067}{300.00} \times 100 = 9.34%

- Hydrogen, H%

\frac{6\times 1}{300.00} \times 100 = 2.0%

- Chlorine, Cl%

\frac{2\times 35.453}{300.00} \times 100 = 23.63%

b. The given reaction of cisplatin is:

K_2PtCl_4(aq)+2NH_3(aq)\rightarrow Pt(NH_3)_2Cl_2(s)+2KCl(aq)

According to the balanced reaction, 1 mole of K_2PtCl_4 gives 1 mole of Pt(NH_3)_2Cl_2.

Now, calculating the number of moles of K_2PtCl_4 in 100.0 g.

Number of moles = \frac{given mass}{Molar mass}

Molar mass of K_2PtCl_4 = 2\times 39.0983+195.084+4\times 35.453 = 415.093 g/mol

Number of moles of K_2PtCl_4 = \frac{100 g}{415.093 g/mol} = 0.241 mole.

Since, 1 mole of K_2PtCl_4 gives 1 mole of Pt(NH_3)_2Cl_2. Therefore, mass of cisplatin is:

0.241 mole\times 300 g/mol = 72.3 g

For mass of KCl:

Molar mass of KCl = 39.0983 + 35.453 = 74.55 g/mol

Since, 1 mole of K_2PtCl_4 gives 2 mole of KCl. Therefore, mass of KCl is:

0.241 mole\times 74.55 g/mol\times 2 = 35.93 g


5 0
3 years ago
Lithium, sodium and potassium are all in group 1 of the periodic table. Which of these has the lowest boiling point?
kvv77 [185]

Answer:

Potassium

Explanation:

In group one of the periodic table both the melting and the boiling points usually decrease down the group.

Now, down the group, it's lithium that comes first, then sodium, then potassium.

Thus, among the 3, potassium is furthermost down the group by virtue of the factor it has the highest atomic number.

Therefore, we can say that potassium has the lowest boiling point among the 3.

5 0
3 years ago
5 Points
GrogVix [38]

Answer:

B

Explanation:

By looking at how seismic waves change speeds as they travel

through Earth

3 0
3 years ago
Read 2 more answers
What environmental condition is most likely to trigger the closing of leaf stoma? Wind, heat, darkness, or lack of moisture
erma4kov [3.2K]
Lack of moisture :)               

8 0
3 years ago
Read 2 more answers
How many grams of glucose are in 11.5 moles?
mestny [16]

There are 2071.79 grams of glucose in 11.5 moles.

8 0
3 years ago
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