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solniwko [45]
2 years ago
12

a compact car is about 1289 kg and its engine has the ability to generate 183831 W. if all that power is applied from a stand st

ill and no energy is dissipated, how fast will the car be moving after 7 seconds.
Physics
1 answer:
Katen [24]2 years ago
8 0

The speed of the car moving after 7 seconds will be 31.5 m/sec.

<h3>What is velocity?</h3>

The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

The given data in the problem is

m is the mass of the car = 1289  Kg.

u is the initial velocity  = 0 m/sec

a is the acceleration in m/sec²

v is the velocity after 7 seconds =?

The power developed is;

P =FV

F=ma

P=maV

183831=1289 kg × a × V

a = 142.61 / V

From Newton's second equation of motion;

V=u+at

V=0+at

V=(142.61/V)t

V²=142.61 × 7

V=31.5 m/sec

Hence, the speed of the car moving after 7 seconds will be 31.5 m/sec.

To learn more about the velocity, refer to the link: brainly.com/question/862972.

#SPJ1

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