1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
solniwko [45]
2 years ago
12

a compact car is about 1289 kg and its engine has the ability to generate 183831 W. if all that power is applied from a stand st

ill and no energy is dissipated, how fast will the car be moving after 7 seconds.
Physics
1 answer:
Katen [24]2 years ago
8 0

The speed of the car moving after 7 seconds will be 31.5 m/sec.

<h3>What is velocity?</h3>

The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

The given data in the problem is

m is the mass of the car = 1289  Kg.

u is the initial velocity  = 0 m/sec

a is the acceleration in m/sec²

v is the velocity after 7 seconds =?

The power developed is;

P =FV

F=ma

P=maV

183831=1289 kg × a × V

a = 142.61 / V

From Newton's second equation of motion;

V=u+at

V=0+at

V=(142.61/V)t

V²=142.61 × 7

V=31.5 m/sec

Hence, the speed of the car moving after 7 seconds will be 31.5 m/sec.

To learn more about the velocity, refer to the link: brainly.com/question/862972.

#SPJ1

You might be interested in
When you changed from low to high power, how did the change affect the working distance of the lens?
Basile [38]

The working distance gets shorter as the magnification gets bigger. In order to focus, the high-power objective lens must be significantly nearer to the specimen than the low-power lens. Magnification is negatively correlated with working distance.

Magnification change The magnification of a specimen is increased by switching from low power to high power. The magnification of an image is determined by multiplying the magnification of the objective lens by the magnification of the ocular lens, or eyepiece.

The geometry of the optical system connects the magnifying power, or how much the thing being observed seems expanded, and the field of view, or the size of the object that can be seen.

To know more about  working distance

brainly.com/question/13551539

#SPJ4

4 0
1 year ago
Which system provides structure and support to the organism?
attashe74 [19]
I found this in a physics tab, I do t know why.
But your answer sir/ma’am is skeleton
3 0
3 years ago
PLEASEEEEE!!!!
Fudgin [204]

Answer:

<h3>The answer is 2.0 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 100 g

volume = 50 mL

We have

density =  \frac{100}{50}  =  \frac{10}{5}  \\

We have the final answer as

<h3>2.0 g/mL</h3>

Hope this helps you

3 0
3 years ago
a 5-kg fish swimming at 1 m/s swallows an absent minded 1-kg fish at rest. What is the speed of the large fish immediately afyer
storchak [24]

Answer:

In first case speed of fish will be \frac{5}{6} m/s.

In the second case the speed of fish \frac{1}{6} m/s

Explanation:

Given data :-

Mass of bigger fish ( m₁ ) = 5 kg.

Mass of small fish ( m₂ ) = 1 kg.

Speed of large fish ( v₁ ) = 1 m/s

Mass of bigger fish after eating smaller one = 5 + 1 = 6 kg.

Case - 1

Momentum of bigger fish before eating the smaller fish = m₁* v₁ = 5 * 1 = 5 kg.m/s

Momentum of bigger fish after eating the larger fish = ( m₁ + m₂)*v

v = speed of bigger fish immediately after lunch.

Using the conservation of momentum.

m₁* v₁ = ( m₁ + m₂)*v

5 = 6 * v

v = \frac{5}{6}  m/s.

Case -2

Speed of small fish = 4 m/s

Momentum of bigger fish before lunch = 5 kg.m/s

Momentum of smaller fish before lunch = 4*1 = 4 kg.m/s

Net momentum before lunch = 5 - 4 = 1 kg.m/s

Momentum of bigger fish after eating the larger fish = 6 * V

Using the conservation of momentum.

1 = 6 * V

V = \frac{1}{6} m/s.

3 0
3 years ago
A microwave oven operates at 2.4 GHz with an intensity inside the oven of 2300 W/m2 . Part A What is the amplitude of the oscill
Tasya [4]

Answer:

The amplitude of the oscillating electric field is 1316.96 N/C

Explanation:

Given;

frequency of the wave, f = 2.4 Hz

intensity of the wave, I = 2300 W/m²

Amplitude of oscillating magnetic field is given by;

B_o = \sqrt{\frac{2\mu_o I}{c} }

where;

μ₀ is permeability of free space = 4π x 10⁻⁷ m/A

I is intensity of wave

c is speed of light = 3 x 10⁸ m/s

B_o = \sqrt{\frac{2*4\pi *10^{-7}*2300}{3*10^8} } \\\\B_o = 4.3899 *10^{-6} \ T

The amplitude of the oscillating electric field is given by;

E₀ = cB₀

E₀ = 3 x 10⁸ x 4.3899 x 10⁻⁶

E₀ = 1316.96 N/C

Therefore, the amplitude of the oscillating electric field is 1316.96 N/C

3 0
3 years ago
Other questions:
  • uring a collision with a wall, the velocity of a 0.200-kg ball changes from 20.0 m/s toward the wall to 12.0 m/s away from the w
    5·1 answer
  • Grace is given a piece of wood, an iron nail, and a styrofoam cup. She puts these objects into a bucket of water and observes th
    12·1 answer
  • When the burner setting is changed to low the burner continues to produce heat?
    13·1 answer
  • What describes how the spring constant affects the potential energy of an object for a given displacement from an equilibrium po
    14·1 answer
  • Why does increasing the number of trials increase confidence in the results of the experiment?
    13·2 answers
  • A series circuit has a 100-Ω resistor, 4.00-mH inductor and a 0.100-μF capacitor connected across a 120-V rms ac source at the r
    9·1 answer
  • What does the big bang theory suggest
    14·1 answer
  • Equipotential surfaces a) make an angle of 45 degrees with the electric field. b) are parallel to the electric field. c) are per
    12·1 answer
  • How many states a water has​
    12·2 answers
  • PLEASE HELP IN ONE MINUTE
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!