Draw all of the Lewis structures of O2 which obey the octet rule and use this Lewis structure or these resonance structures to p
redict how many covalent bonds connect each oxygen atom in the real structure to the central O atom. Assume that the octet rule is followed for the O atom when you draw your structure(s). Pick the correct statement from the choices below. a) Each oxygen atom is connected to the central O atom with 1.67 covalent bonds. b) Each oxygen atom is connected to the central O atom with 1.33 covalent bonds. c) Each oxygen atom is connected to the central O atom with 2 covalent bonds. d) Each oxygen atom is connected to the central O atom with 1.5 covalent bonds. e) Each oxygen atom is connected to the central O atom with 1.25 covalent bonds.
1 answer:
Answer:
Each oxygen atom is connected to the central O atom with 2 covalent bonds.
Explanation:
Oxygen atoms are connected by two covalent bonds in the oxygen molecule from the Lewis structure, we see that the bond order for O2 is 2 (a double bond) this is clearly seen in the image attached. There are no resonance structures for the oxygen molecule since there are no partial bonds in the molecule, only the two covalent bonds present.
This structure of oxygen shown in the image is its only structure, showing the covalent bonds formed and other non bonding electrons present in the molecule. The octet rule is followed in drawing the structure. Each oxygen atom possesses an octet of electrons on its outermost shell.
You might be interested in
Answer:
The dots were not properly located and arrows are not used in Lewis structures
Explanation:
If we intend to write a Lewis structure for a compound, that lewis structure must consist of only dots. These dots actually show the valence electrons on the outermost shell of the molecule.
We do not involve arrows when writing dot electron structures for compounds. The valence electrons of magnesium ought not to be written together because they are not a lone pair, rather they are two unpaired electrons. The use of an arrow suggests a coordinate covalent bond which is not the case here.
The correct lewis structure for MgCl2 is shown in the image attached to this answer.
Answer : The resulting concentrations of CV and NaOH are 0.0027 M and 0.025 M respectively.
Explanation :
Step 1 : Find moles of crystal violet and NaOH.
The molarity formula is
Molarity of crystal violet =
The volume of crystal violet solution is 18 mL which is 0.018 L.
Moles of crystal violet =
Moles of crystal violet = 5.4 x 10⁻⁵
Moles of NaOH =
Moles of NaOH = 5.00 x 10⁻⁴
Step 2 : Find total volume of the solution
The total volume of the solution after mixing NaOH and crystal violet is
0.018 L + 0.00200 = 0.020 L
Step 3 : Use molarity formula to find final concentrations
Molarity of crystal violet =
Final concentration of CV = 0.0027 M
Molarity of NaOH=
NaOH is a strong base and dissociates completely as follows.
The mole ratio of NaOH and OH⁻ is 1:1 . Therefore the concentration of OH⁻ is same as that of NaOH.
Concentration of OH⁻ = 0.025 M