Draw all of the Lewis structures of O2 which obey the octet rule and use this Lewis structure or these resonance structures to p
redict how many covalent bonds connect each oxygen atom in the real structure to the central O atom. Assume that the octet rule is followed for the O atom when you draw your structure(s). Pick the correct statement from the choices below. a) Each oxygen atom is connected to the central O atom with 1.67 covalent bonds. b) Each oxygen atom is connected to the central O atom with 1.33 covalent bonds. c) Each oxygen atom is connected to the central O atom with 2 covalent bonds. d) Each oxygen atom is connected to the central O atom with 1.5 covalent bonds. e) Each oxygen atom is connected to the central O atom with 1.25 covalent bonds.
1 answer:
Answer:
Each oxygen atom is connected to the central O atom with 2 covalent bonds.
Explanation:
Oxygen atoms are connected by two covalent bonds in the oxygen molecule from the Lewis structure, we see that the bond order for O2 is 2 (a double bond) this is clearly seen in the image attached. There are no resonance structures for the oxygen molecule since there are no partial bonds in the molecule, only the two covalent bonds present.
This structure of oxygen shown in the image is its only structure, showing the covalent bonds formed and other non bonding electrons present in the molecule. The octet rule is followed in drawing the structure. Each oxygen atom possesses an octet of electrons on its outermost shell.
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The mass of the Pbl2 : 1308.87
<h3>Further explanation</h3>Given
18.2 mL of a 0.156 M Pb(NO3)2
26.2 mL of a 0.274 M KI
Reaction
Pb(NO3)2 (aq) + 2 KI (aq) - Pbl2 (s) + 2 KNO3
Required
the mass of the Pbl2
Solution
mol Pb(NO3)2 = 18.2 x 0.156 = 2.8392 mlmol
mol KI = 26.2 x 0.274 =7.1788 mol
Limiting reactant Pb(NO3)2(smaller ratio of mol : reaction coeffiecient)
mol Pbl2 based on limiting reactant (Pb(NO3)2)
From equation, mol ratio of Pb(NO3)2 : Pbl2 = 1 : 1, so mol Pbl2=mol Pb(NO3)2=2.8392
Mass Pb(NO3)2 :