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olga55 [171]
3 years ago
8

Draw all of the Lewis structures of O2 which obey the octet rule and use this Lewis structure or these resonance structures to p

redict how many covalent bonds connect each oxygen atom in the real structure to the central O atom. Assume that the octet rule is followed for the O atom when you draw your structure(s). Pick the correct statement from the choices below. a) Each oxygen atom is connected to the central O atom with 1.67 covalent bonds. b) Each oxygen atom is connected to the central O atom with 1.33 covalent bonds. c) Each oxygen atom is connected to the central O atom with 2 covalent bonds. d) Each oxygen atom is connected to the central O atom with 1.5 covalent bonds. e) Each oxygen atom is connected to the central O atom with 1.25 covalent bonds.

Chemistry
1 answer:
ryzh [129]3 years ago
7 0

Answer:

Each oxygen atom is connected to the central O atom with 2 covalent bonds.

Explanation:

Oxygen atoms are connected by two covalent bonds in the oxygen molecule from the Lewis structure, we see that the bond order for O2 is 2 (a double bond) this is clearly seen in the image attached. There are no resonance structures for the oxygen molecule since there are no partial bonds in the molecule, only the two covalent bonds present.

This structure of oxygen shown in the image is its only structure, showing the covalent bonds formed and other non bonding electrons present in the molecule. The octet rule is followed in drawing the structure. Each oxygen atom possesses an octet of electrons on its outermost shell.

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Answer:

2.25g of NaF are needed to prepare the buffer of pH = 3.2

Explanation:

The mixture of a weak acid (HF) with its conjugate base (NaF), produce a buffer. To find the pH of a buffer we must use H-H equation:

pH = pKa + log [A-] / [HA]

<em>Where pH is the pH of the buffer that you want = 3.2, pKa is the pKa of HF = 3.17, and [] could be taken as the moles of A-, the conjugate base (NaF) and the weak acid, HA, (HF). </em>

The moles of HF are:

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Replacing:

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[A-] = 0.0500mol * 1.017152

[A-] = 0.0536 moles NaF

The mass could be obtained using the molar mass of NaF (41.99g/mol):

0.0536 moles NaF * (41.99g/mol) =

<h3>2.25g of NaF are needed to prepare the buffer of pH = 3.2</h3>
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