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3 years ago

What is the net force on this object: F norm = 20N F frict = 14N F app = 22N F grav = 20N?

Physics

2 answers:

sergey [27]3 years ago

8 0

Answer:

8N is the net force on the object.

Explanation:

Given that,

$\mathrm{F}_{\text {norm }}$ =20N is normal force acting upward (+20N)

$F_{\text {frict }}$ =14N is frictional force which is opposite to the applied force (-14N)

$\mathrm{F}_{\mathrm{app}}=$ 22N is applied force which is applied on right side (+22N)

$\mathrm{F}_{\mathrm{grav}}$ =20N is gravitational force acting downward (-20N)

We know that ,

$\text { Fnet }$ =applied force $\left(\mathrm{F}_{\mathrm{app}}\right)$ +frictional force $\left(F_{\text {frict }}\right)$ +normal force $\left(\mathrm{F}_{\mathrm{norm}}\right)$ +gravitational force $\left(F_{\text {grav}}\right)$

$\mathrm{F}_{\mathrm{net}}=$ 22+(-14)+ 20+(-20)

$\mathrm{F}_{\mathrm{net}}=$ 22-14+20-20

$\mathrm{F}_{\mathrm{net}}=8 \mathrm{N}$

Therefore the net force of the object be 8N.

viva [34]3 years ago

4 0

Answer:

8N i believe

Explanation:

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Answer:

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Explanation:

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Answer:

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2 years ago

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