Answer:
Explanation:
The weight of the box is
W = 253.1N
Weight is on an incline plane
θ = 39.7°
The weight of an object is always acting downward
So, the weight makes an angle of 39.7° with the vertical component
Then, it's horizontal component is
Wx = W•Sinθ
Wx = 253.1 × Sin 39.7°
Wx = 161.67 N
The horizontal component of the weight is 161.67N
This is the force acting down the plane.
Check attachment
Answer:
New pressure of the gas increases by 26.5% with respect to initial pressure, new volume decreases 27% with respect to initial volume and new temperature decreases 8% with respect to initial volume.
Explanation:
If we assume the gas is a perfect gas we can use the perfect gas equation:
(1)
Where subscripts 1 shows before the isothermal process and 2 after it, because isothermal means constant temperature T1=T2, and pressure increases by 10% means P2=1,1*P1, using these facts on (1) we have:
(2)
(3)
Where subscripts 2 shows before the isobaric process and 3 after it, because isobaric means constant pressure P2=P3, and volume decreases by 20% means V3=0.8*V2, using these facts on (3) we have:
(4)
(5)
Where subscripts 3 shows before the isochoric process and 4 after it, because isochoric means constant volume V3=V4, and temperature increases by 15% means T4=1.15*T3, using these facts on (5) we have:
(6)
So now because P4=1.15*P3, P2=P3 and P2=1.1*P1:
This is, the new pressure of the gas increases by 26.5% with respect to initial pressure.
Similarly, we have V3=V4, V3=0.8*V2 and V1=1,1*V2:
so the final volume decreases 27% with respect to initial volume.
T4=1,15*T3, T3=0.8*T2 and T1=T2:
The new temperature decreases 8% with respect to initial volume.
Answer:
The horizontal distance traveled by the projectile is 15.23 m.
Explanation:
Given;
angle of projection, θ = 25⁰
initial velocity of the projectile, u = 15 m/s
time of flight, t = 1.12 s
The the travelling path of the object is calculated as the range of the projectile
Therefore, the horizontal distance traveled by the projectile is 15.23 m.