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Ostrovityanka [42]
1 year ago
9

b) Explain what happens when a drop of concentrated sugar solution is placed on a rheo leaf peel mounted on a glass slide. Name

this phenomenon. Would the same happen if the rheo leaf was boiled before mounting? Give reason for your answer
Chemistry
1 answer:
user100 [1]1 year ago
6 0

The rheo leaf peel will lose water by osmosis and become flaccid. If the rheo leaf was boiled, this would not happen.

<h3>What is osmosis?</h3>

Across living membranes, water moves from a region of high to a region of low water potential.

Concentrated sugar solutions have low water potential when compared to the cell sap of the cells of rheo leaf peel. Thus, water will move from the rheo leaf peel to the sugar solution.

This will result in the wilting of the leaf peel.

If the leaf peel is boiled, the membranes in the cells die and can no longer function as a selectively permeable interface.

More on osmosis can be found here: brainly.com/question/1799974

#SPJ1

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Suppose you wanted to dissolve 40.0 g NaOH in enough H2O to make 6.00 dm3 of solution
dezoksy [38]

Molarity of solution = 1.6 M

<h3>Further explanation</h3>

Given

40 g NaOH

6 L solution

Required

Steps to solve the problem of molarity

Solution

No additional information about the question.

If you want to make the solution above, then we just need to put the existing NaOH (40 g) into 6 L of water, then do the stirring (in a warm temperature above the hot plate will speed up the NaOH dissolving process)

But if you want to know the molarity of a solution, then

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\tt mol=\dfrac{mass}{MW}

MW(molecular weight) of NaOH=

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23 + 16 + 1 = 40 g/mol

so mol NaOH :

\tt mol=\dfrac{40~g}{40~g/mol}=1~mol

  • 2. Molarity(M)

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