45.8 grams of copper requires 1172 J of heat to reach a final temperature of 100.5 ℃. What was the initial temperature? Specific
1 answer:
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7.86 is the pOH of water at this temperature of 100 degrees celsius.
Option E is the right answer.
Explanation:
Data given:
Kw = 51.3 x
pOH = ?
we know that pure water is neutral and will have pH pf 7.
The equation for relation between Kw and H+ and OH- ion is given by:
Kw = [H+] [OH-}
here the concentration of H+ ion and OH- ion is equal
so, [H+]= [OH-]
Putting the values in the equation of Kw
pKw = -log[Kw]
pKw = -log [51.3 x ]
pKw = 12.28
since H+ ion OH ion concentration is equal the pH of water is half i.e. 6.14
Now, pOH is calculated by using the equation:
14 = pOH + pH
14- 6.14 = pOH
pOH = 7.86
Correct option:
The correct name for is diphosphorus pentoxide.
Why is called diphosphorus pentoxide?
is commonly known as diphosphorus pentoxide.
Phosphorus pentoxide has an intriguing property in that is actually its empirical formula, whereas
is its actual molecular formula.
However, the name of the chemical was obtained from its empirical formula rather than from its molecular formula. The official name for this substance is diphosphorus pentoxide.
Oxygen-containing binary compounds have "oxide" as their "last name." Phosphorus is the "first name."
We list each atom's numbers below:
The di- and Penta- prefixes are used to indicate the presence of two and five oxygen atoms, respectively, in the molecule.
Learn more about diphosphorus pentoxide here,
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