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Fiesta28 [93]
1 year ago
8

your manger wants everyine to make setting up seasonal aisle display their top priority you noticed one if associate benn focusi

ng on other task mostly likly to do or least likly to do
Physics
1 answer:
Sauron [17]1 year ago
5 0

The manager is both most and least likely to lead seminars and provide everyone skills.

<h3 /><h3>What is seasonal aisle?</h3>

When a store has a “seasonal aisle,” it suggests it has extra money to spend on items that are in season. Festivals, special days, seasons, and other things are examples of seasonal components.

An operational strategy focused on creating profit. Seasonal goods are required by a supply chain. A manager wants everyone to prioritize setting up the seasonal aisle displays because of this.

Hence, the significance of the seasonal aisle is aforementioned.

Learn more about on manager, here:

brainly.com/question/11599959

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The boy’s foot causes the motion. His foot is the one that causes the ball to roll down the hill.
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How is a projectile different from an object in free fall
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Explanation:

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3. If I run 150m in 30 seconds, what speed will I have been running at?
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If a boy with 50kg run in 3m/s what is his velocity
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Read 2 more answers
*A car is going through a dip in the road whose curvature approximates a circle of radius 150m. At what velocity will the occupa
Valentin [98]

Answer:

v= 14.85 m/s

Explanation:

  • When at the bottom of the dip, the only force that keeps the car in the circular trajectory, is the centripetal force.
  • This force is not a new force, is just the net force aiming to the center of the circle.
  • In this case, is just the difference between the normal force (always perpendicular to the surface, pointing upward) and the force that gravity exerts on the car (which is known as the weight), pointing downward.
  • So, we can write the following expression:

       F_{cent} = F_{n} - F_{g}  (1)

  • It can be showed that the centripetal force is related to the speed by the following expression:
  • F_{cent} = m*\frac{v^{2}}{r} (2)
  • The normal force, it is called the apparent weight, because it would be the weight as measured by a scale.
  • Replacing (2) in (1), and solving for Fn, we get:

       F_{n} = m*\frac{v^{2} }{r} + m*g (3)

  • Now, we need to find the value of v that makes Fn, exactly 15% more than the weight m*g, so we can write the following equation:

      F_{n} = 1.15*F_{g} = m*\frac{v^{2}}{r} +F_{g}  (4)

  • Replacing Fg by its value, simplifying, and solving for v, we get:

       v = \sqrt{0.15*g*r} = \sqrt{9.8 m/s2*0.15*150m} = 14.85 m/s (5)

3 0
2 years ago
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