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bezimeni [28]
2 years ago
5

During the distillation nitrogen gas is obtained first, then argon and oxygen. What can u say about the boiling points of these

three gases?
Chemistry
2 answers:
svetlana [45]2 years ago
6 0

Explanation:

The boiling point of liquid nitrogen, liquid argon, and liquid oxygen are -196°C, -186°C, and -183°C respectively. So, the correct order is nitrogen, argon, oxygen.

marissa [1.9K]2 years ago
5 0

Nitrogen:

Since you don't want nitrogen to be condensing everywhere when it gets cold out, elemental nitrogen's boiling point is luckily below zero degrees Celsius. Thank goodness for nitrogen's extremely low boiling point. If it were at zero, boiling water would not produce a lot of heat, necessitating the use of a pressure cooker to prepare foods that typically call for boiling water. Additionally, since the air would be substantially enhanced with oxygen, items may catch fire more quickly (i.e. your home might burst in flame that much more easily). An ugly picture, to be sure.

Argon:

As nonpolar gases, Ar, F2, and Cl2 only display London Dispersion Forces (LDF). These largely negligible forces, which are the product of transient dipoles, must be resisted throughout the boiling process. Since bigger atoms and molecules have valence electrons further from their nucleus, LDF intensity is also directly correlated with atomic or molecular size. Compared to smaller atoms or molecules, these outermost electrons are less attracted to the positive nucleus or nuclei, making it simpler for them to create transient dipoles. As a result, the differing molar masses of each compound—Ar—39.95 g/mol, F—38.00 g/mol, and Cl—70.90 g/mol—can be used to explain the variation in boiling points.

Oxygen:

At 1 atm, oxygen would boil at -183 degrees Celsius if it were a liquid. Although the phase diagram for oxygen is more intricate than this, it is a general phase diagram. Imagine that the term "vaporization" is at the same height as 1 atm, which is roughly halfway up the y-axis. If the y value at that time was equal to 1 atm, the "vaporization" arrow to the right would be directly above -183 degrees Celsius. It's crucial to remember that pressure determines what temperature a substance will boil, melt, condense, or freeze, as you can probably guess. Additionally, the pressure in particular circumstances can affect what phase a material is in.

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Sergeu [11.5K]

A saturated is one in which the atoms are linked by single bonds. :)

5 0
3 years ago
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If an alloy is formed that is 50 mol% silver and 50 mol% gold, what is the karat number of the alloy?
Allisa [31]
Answer : 12 karat

Explanation : When pure gold is considered to be 24 karat then if its 50 mol% silver and 50 mol% silver then using karat scale calculation;

Karat/24 X 100 = 50 mol% (for gold) in alloy

So, Karat = (50 X 24) / 100 = 12 karat.

Hence the alloy will be of 12 karat.
7 0
3 years ago
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Calculate how many times more soluble Mg(OH)2 is in pure water Based on the given value of the Ksp, 5.61×10−11, calculate the ra
maks197457 [2]

Answer:

molar solubility in water = 2.412 * 10^-4  mol/L

molar solubility of NaOH in 0.130M = 3.32 * 10^-9 mol/L

Mg(OH)2 is a factor 0.73*10^5 more soluble in pure water than in 0.130 M NaOH

Explanation:

The Ksp refers to the partial solubilization of a mostly insoluble salt. This is an equilibrium process.

 

The equation for the solubilization reaction of Mg(OH)2 can be given as:

 

Mg(OH)2 (s) → Mg2+ (aq) + 2OH– (aq)

 Ksp can then be given as followed:

Ksp = [Mg^2+][OH^–]²  

<u>Step 2:</u> Calculate the solubility in water

Mg(OH)2 (s) → Mg2+ (aq) + 2OH– (aq)

The mole ratio Mg^2+ with OH- is 1:2

So there will react X of Mg^2+ and 2X of OH-

The concentration at equilibrium will be XM Mg^2+ and 2X OH-

Ksp = [Mg^2+][OH^–]²  

5.61*10^-11 = X * (2X)² = X *4X² = 4X³

 X = <u>2.412 * 10^-4 mol/L = solubility in water</u>

<u>Step 3</u>: Calculate solubility in 0.130 M NaOH

The initial concentration of Mg^2+  = 0 M

The initial concentration of OH- = 0.130 M

The mole ratio Mg^2+ with OH- is 1:2

So there will react X of Mg^2+ and 2X +0.130 for OH-

The concentration at equilibrium will be XM Mg^2+ and 0.130 + 2X OH-

The value of "[OH–] + 2X" is, because the very small value of X, equal to the value of [OH–] .

Let's consider:

[Mg+2] = X

[OH] = 0.130

Ksp = [Mg^2+][OH^–]²  

5.61*10^-11 = X *(0.130)²  

5.61*10^-11 = X * (0.130)^2

X = <u>3.32*10^-9 = solubility in 0.130 M NaOH </u>

<u>Step 4:</u> Calculate how many times Mg(OH)2 is better soluble in pure water.

(2.412*10^-4)/ (3.32*10^-9) = 0.73 * 10^5

Mg(OH)2 is a factor 0.73*10^5 more soluble in pure water than in 0.130 M NaOH

4 0
3 years ago
Select all the correct answers.
Andrei [34K]

Scientists use scientific notation to communicate extremely small measurements. Hence, option A is correct.

<h3>What scientific notation?</h3>

Scientific notation is a way of writing very large or very small numbers.

Scientists use scientific notation to represent very small or very large numbers because this notation increases the  

  • accuracy of measured quantities.

  • convenience in using the numbers.

  • the number of significant figures.

  • precision of measurements.

Hence, option A is correct.

Learn more about the scientific notation here:

brainly.com/question/18073768

#SPJ1

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2 years ago
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babymother [125]
Below are the choices:

A The mercury will change temperature at a much faster rate under the same heating conditions. 
<span>B The two metal samples will change temperature at about the same rate. </span>
<span>C The gold would float if placed in the mercury. </span>
<span>D The gold would sink to the bottom if placed in the mercury.
</span>
  <span>a = false, it will take 0.031 cal to raise 1g Au 1degree while it will take 0.033 cal to raise 1g Hg 1 degree so, although Au will heat up faster, it will not be discernably faster so... 
b = true 
c = false, Au density > Hg 
d = true</span>
7 0
3 years ago
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