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Wittaler [7]
3 years ago
6

Sodium chloride (NaCl) is an ionic solid. It dissolves easily in water. Which property of water allows it to dissolve NaCl?

Chemistry
2 answers:
kkurt [141]3 years ago
5 0
Water is a polar molecule.
ludmilkaskok [199]3 years ago
5 0

Answer:

Explanation:

Sodium chloride and water both are polar molecules thus it dissolves easily in water hence the correct answer is D water is a polar molecule.

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Crazy boy [7]

Answer:

<u>5 moles S x (36.02 g S/mole S) = 180.1 grams of S</u>

Explanation:

The periodic table has mass units for every element that can be correlated with the number of atoms of that element.  The relationship is known as Avogadro's Number.  This number, 6.02x10^{23} , is nicknamed the mole, which scientists found to be a lot more catchy, and easier to write than  6.02x10^{23}.  <u>The mole is correlated to the atomic mass of that element.</u>  The atomic mass of sulfur, S, is 36.02 AMU, atomic mass units.  <u>But it can also be read as 36.02 grams/mole.</u>

<u></u>

<u>This means that 36.02 grams of S contains 1 mole (6.02x</u>10^{23}<u>) of S atoms</u>.

<u></u>

This relationship holds for all the elements.  Zinc, Zn, has an atomic mass of 65.38 AMU, so it has a "molar mass" of 65.38 grams/mole.  ^5.38 grams of Zn contains 1 mole of Zn atoms.  

And so on.

5.0 moles of Sulfur would therefore contain:

(5.0 moles S)*(36.02 grams/mole S) = <u>180.1 grams of S</u>

Note how the units cancel to leaves just grams.  The units are extremely helpful in mole calculations to insure the correct mathematical operation is done.  To find the number of moles in 70 g of S, for example, we would write:

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4 0
2 years ago
What volume of 1.00 m hcl in liters is needed to react completely (with nothing left over) with 0.750 l of 0.100 m na2co3?
kotykmax [81]
The balanced equation for the reaction is as follows
Na₂CO₃ + 2HCl --> 2NaCl + CO₂ + H₂O
stoichiometry of Na₂CO₃ to HCl is 1:2
number of Na₂CO₃ moles reacted = molarity x volume
number of Na₂CO₃ moles = 0.100 mol/L x 0.750 L = 0.0750 mol 
according to molar ratio of 1:2
1 mol of Na₂CO₃ reacts with 2 mol of HCl
then 0.0750 mol of Na₂CO₃ mol reacts with - 2 x 0.0750 = 0.150 mol 
molarity of given HCl solution is 1.00 mol/L
molarity is defined as the number of moles of solute in 1 L of solution 
there are 1.00 mol in 1 L of solution 
therefore there are 0.150 mol in - 0.150 mol / 1.00 mol/L = 0.150 L 
volume of HCl required is 0.150 L 
3 0
3 years ago
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