Decomposition of a potassium superoxide happens according to the scheme:
4KO₂(s) + 2H₂O(l) → 4KOH(aq) + 3O₂(g)
m(K₂O)=4M(K₂O)m(O₂)/{3M(O₂)}
m(K₂O)=4×71.1×6.5/{3×32.0}≈19.3 g
Answer:
Q = 1360.248 j
Explanation:
Given data:
Mass of brass = 298.3 g
Initial temperature = 30.0°C
Final temperature = 150°C
Specific heat capacity of brass = 0.038 J/g.°C
Heat absorbed = ?
SOLUTION:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 150°C - 30.0°C
ΔT = 120°C
Q = 298.3 g × 0.038 J/g.°C × 120°C
Q = 1360.248 j
Answer:
Obtain the conversion factor by dividing the required yield (from Step 2) by the old yield (from Step 1). That is, conversion factor = (required yield)/(recipe yield) or conversion factor = what you NEED ÷ what you HAVE.
Explanation:
Answer:
See explanation
Explanation:
Now , we have the equation of the reaction as;
2H2S(g) + 302(g)------->2SO2(g) + 2H2O(g)
This equation shows that SO2 gas is produced in the process. Let us recall that this same SO2 gas is the anhydride of H2SO4. This means that it can dissolve in water to form H2SO4
So, when SO2 dissolve in rain droplets, then H2SO4 is formed thereby lowering the pH of rain water. This is acid rain.
Answer is: Te (tellurium).
During electron capture, iodine-123 f<span>orm the nearly-stable nuclide tellurium-123.
</span>In beta
plus decay (atomic number Z is decreased by one), a proton is converted to a neutron
and positron and an electron neutrino, so mass <span>number does not
change.
</span>Iodine-123 is a radioactive isotope of iodine used in nuclear medicine imaging.<span>
</span>
