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2 years ago

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2. Two charges 160μC and -250μC are placed together at a distance of 150 centimeter apart. Find the force of attraction between

each other. Also explain the nature of the force [Repulsing force = +ve, Attraction force = -ve]

1 answer:

n200080 [17]2 years ago

4 0

The answer is -0.016 N, and as it negative, the nature of the force is attractive.

<u>Finding the force of attraction</u>

Coulomb's Law is given by :

$\boxed {F = \frac{kq_{1}q_{2}}{r^{2}}}$

<u>Solving</u>

F = 9 × 10⁹ × 160 × 10⁻⁶ × -250 × 10⁻⁶ / (150 × 10⁻³)²
F = -360000 × 10⁻³ / 22500 × 10⁻⁶
F = -16 × 10⁻³
F = -0.016 N

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