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Paul [167]
3 years ago
11

What is Sonogram?Name one use of sonogram.

Physics
1 answer:
Blizzard [7]3 years ago
8 0

Answer:

<em>Sonogram </em><em>is </em><em>a </em><em>medical </em><em>image </em><em>produced </em><em>by </em><em>ultrasound </em><em>echo. </em>

<em>It </em><em>is </em><em>used </em><em>to </em><em>help</em><em> </em><em>diagnose </em><em>causes </em><em>of </em><em>pain </em><em>and </em><em>swelling</em><em>. </em>

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These graphs show measurements of the density of air as different sound waves pass a single point.
Ymorist [56]

Answer: D!

It is the option with the greatest amplitude.

5 0
3 years ago
Read 2 more answers
A block–spring system vibrating on a frictionless, horizontal surface with an amplitude of 7.0 cm has an energy of 14 J. If the
Bingel [31]

Answer:

E_T= 28J

Explanation:

The energy of Mass-Spring System the sum of the potential energy of the block plus the kinetic energy of the block:

E_T=U+K=\frac{1}{2} k \Delta x^2+\frac{1}{2} mv^2

Where:

\Delta x=Amplitude\hspace{3}or\hspace{3}d eformation\hspace{3} of\hspace{3} the\hspace{3} spring\\m=Mass\hspace{3}of\hspace{3}the\hspace{3}block\\k=Constant\hspace{3}of\hspace{3}the\hspace{3}spring\\v=Velocity\hspace{3}of\hspace{3}the\hspace{3}block

There are two cases, the first case is when the spring is compressed to its maximum value, in this case the value of the kinetic energy is zero, since there is no speed, so:

E_T=\frac{1}{2} k \Delta x^2\\\\14=\frac{1}{2} k7^2\\\\Solving\hspace{3} for\hspace{3} k\\\\k=\frac{28}{49} =\frac{4}{7}

The second case is when the block passes through its equilibrium position, in this case the elastic potential energy is zero since \Delta x=0, so:

E_T=\frac{1}{2} mv^2\\\\14=\frac{1}{2} mv^2\\\\Solving\hspace{3} for\hspace{3} v\\\\v^2=\frac{28}{m}

Now, let's find the energy of the system when the block is replaced by one whose mass is twice the mass of the original block using the previous data:

E_T=U+K=\frac{1}{2} k \Delta x^2+\frac{1}{2} m_2v^2

Where in this case:

m_2=New\hspace{3}mass=Twice\hspace{3} the\hspace{3} mass \hspace{3}of\hspace{3} the\hspace{3} original=2m

Therefore:

E_T=\frac{1}{2} (\frac{4}{7} ) (7^2)+\frac{1}{2} (2m)(\frac{28}{m_2})=\frac{1}{2} (\frac{4}{7} ) (7^2)+\frac{1}{2} (2m)(\frac{28}{2m})=14+14=28J

8 0
3 years ago
There are 8.8 liters of gas in a piston at a pressure of 1.75 atmospheres. The temperature remains constant, and the gas is comp
saveliy_v [14]

The new pressure P2 is 2.48 atmosphere.

<u>Explanation:</u>

Here, the one of the product of pressure and volume is equal to the products of pressure and volume of other.

By using Boyles's law,

               pressure is inversely proportional to volume,

                                         P1 V1 = P2 V2

where P1, V1 represents the first pressure and volume,

           P2, V2 represents the second pressure and volume

                                              P2 = (P1 V1) / V2

                                                    = (1.75 \times 8.8) / 6.2

                                              P2  = 2.48 atmosphere.  

         

5 0
3 years ago
Please help I'll mark brainliest NO LINKS
Bond [772]

Answer:C

Explanation:

7 0
3 years ago
A capacitor is not the most efficient device for storing energy. Batteries can store more energy in much less space. For example
photoshop1234 [79]

Answer:

A=2.49\times 10^6\ m^2

Explanation:

Given that

Stored energy E

U=10^6\ J

a)

We know that stored energy in capacitor given as

U=\dfrac{1}{2}CV^2

Given that

V=10^4\ V

U=\dfrac{1}{2}CV^2

10^6=\dfrac{1}{2}\times C\times (10^4)^2

C= 0.02 F

b)

Electric filed E = 9 x 10^6 V/m

We know that

V = E .d

10^4=9\times 10^6\times d

d=1.11 mm

We know that

C=\dfrac{\varepsilon _oA}{d}

0.02=\dfrac{8.89\times 10^{-12}A}{1.11\times 10^{-3}}

A=2.49\times 10^6\ m^2

This is area  area of the plates.

5 0
3 years ago
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