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MAXImum [283]
2 years ago
14

A lighter like the one shown below uses a substance called butane as its fuel. The butane can be burned to create a flame at the

tip of the lighter.
a butane lighter


A teacher shows some of her students that the fuel inside the lighter's fuel tank is a liquid. But when she pushes the button that lets the fuel out of the lighter, they observe that it comes out as a gas. She and her students decide to investigate to discover what makes the butane change from a liquid to a gas.


Which step of an investigation would best help them determine what causes the change of state?

A.

calculating the volume of the lighter's fuel tank

B.

comparing lighters that use different kinds of fuel

C.

measuring the pressure inside the lighter's fuel tank

D.

heating butane gas to see if it changes state
Chemistry
1 answer:
Nookie1986 [14]2 years ago
6 0

Part of the investigation must be measuring the pressure inside the lighter fuel tank.

<h3>What is the pressure of a gas?</h3>

The pressure of gas measures how compact the gas molecules are. We know that the more compacted the gas molecules are, the more likely the gas will exist in the liquid state.

Hence, part of the investigation must be measuring the pressure inside the lighter  fuel tank.

Learn more about pressure of a gas:brainly.com/question/356658

#SPJ1

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A chemist prepares a solution of magnesium chloride MgCl2 by measuring out 49.mg of MgCl2 into a 100.mL volumetric flask and fil
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Answer:  Molarity of Cl^- anions in the chemist's solution is 0.0104 M

Explanation:

Molarity : It is defined as the number of moles of solute present per liter of the solution.

Formula used :

Molarity=\frac{n\times 1000}{V_s}

where,

n= moles of solute

Moles=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{0.049g}{95g/mol}=5.2\times 10^{-4}moles  

V_s = volume of solution in ml = 100 ml

Now put all the given values in the formula of molarity, we get

Molarity=\frac{5.2\times 10^{-4}moles\times 1000}{100ml}=5.2\times 10^{-3}mole/L

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As 1 mole of MgCl_2 gives 2 moles of Cl^-

Thus 5.2\times 10^{-3}  moles of MgCl_2 gives =\frac{2}{1}\times 5.2\times 10^{-3}=0.0104

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