Answer:
(A) Th = 818.6 K
(B) Qh = 14211.7 J
Explanation:
efficiency (n) = 0.537
temperature of cold reservoir (Tc) = 379 K
heat rejected (Qc) = 6580 J
(A) find the temperature of the hot reservoir (Th)
n = 1 - 
0.537 = 1 - 
= 1 - 0.537 = 0.463
Th = 
Th = 818.6 K
(B) what amount of heat is put into the engine (Qh) ?
from 
Qh = 6580 ÷ 
Qh = 14211.7 J
There are three factors:
The charge of the two objects. The electric force is proporcional to the product of the charges of both objects.
The distance that separetes them. The electric force is proportional to the inverse of the squared distance that separates the objects.
The media. The electric force constant of proportionality depends on the media: air, water, oil, glass.
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Answer:
3300J
Explanation:
Work done is the energy that is lost by the skater
Formula for workdone = 1/2*mV^2
m = 66kg
V = 10m/s
Work done = 1/2 * 66 * 10^2
= 3300J
Answer:
voltage is 1.38 V
Explanation:
given data
weights = 150 gm = 0.150 kg
sensitivity = 0.5 volts/Newton
to find out
large a voltage
solution
we know here in by symmetry so here in x axis
F3 will be
F3 = 2mgcos(20)
F3 = 2(0.150)(9.8)cos20
F3 = 2.76 N
so volatge is
voltage = 2.76×sensitivity
voltage = 2.76×0.5
voltage = 1.38
so voltage is 1.38 V
