Atoms, molecules, electrons, photons, protons etc.
<span>the ratio of the velocity of light in the medium over the velocity of light in a vacuum</span>
Answer:
The answer to the question is;
The total potential energy of the mass on the spring when the mass is at either endpoint of its motion is 5.0255 Joules.
Explanation:
To answer the question, we note that the maximum speed is 2.30 m/s and the mass is 1.90 kg
Therefore the maximum kinetic energy of motion is given by
Kinetic Energy, KE =
Where,
m = Attached vibrating mass = 1.90 kg
v = velocity of the string = 2.3 m/s
Therefore Kinetic Energy, KE =
×1.9×2.3² = 5.0255 J
From the law of conservation of energy, we have the kinetic energy, during the cause of the vibration is converted to potential energy when the mass is at either endpoint of its motion
Therefore Potential Energy PE at end point = Kinetic Energy, KE at the middle of the motion
That is the total potential energy of the mass on the spring when the mass is at either endpoint of its motion is equal to the maximum kinetic energy.
Total PE = Maximum KE = 5.0255 J.
To solve this problem we will apply the concepts related to the work theorem for which it is defined as the product of Force and distance. In turn, we will use the energy conservation theorem for which the applied work must be equivalent to the total kinetic energy on the body.
The work is defined as

Here,
F = Force
d = Displacement
Replacing with our values we have that


Now by conservation of energy,



Solving for v,


Therefore the correct answer is D.
Answer: 
Explanation:
We are told both planets describe a circular orbit around the star S. So, let's approach this problem begining with the angular velocity
of the planet P1 with a period
:
(1)
Where:
is the velocity of planet P1
is the radius of the orbit of planet P1
Finding
:
(2)
(3)
(4)
On the other hand, we know the gravitational force
between the star S with mass
and the planet P1 with mass
is:
(5)
Where
is the Gravitational Constant and its value is 
In addition, the centripetal force
exerted on the planet is:
(6)
Assuming this system is in equilibrium:
(7)
Substituting (5) and (6) in (7):
(8)
Finding
:
(9)
(10)
Finally:
(11) This is the mass of the star S