Explanation:
As it is given that hot pan of copper is dropped into a tub of hot water and the temperature of water rises. This means that heat from the pan has been released and this heat is gained by water.
As a result, temperature of copper pan has decreased and this decrease will continue till the time temperature of both copper pan and water will reach the same temperature.
As thermal energy is defined as the energy in which when two objects come in physical contact with each other then no exchange of heat energy will take place.
Thus, we can conclude that when temperature of both copper pan and water will be equal then it means that both of them has reached thermal equilibrium.
I got B,when you subtract 3/5 from NEGATIVE 2/3 it creates a negative 19 over a positive 15.
Answer:

Explanation:
For answer this we will use the law of the conservation of the angular momentum.

so:

where
is the moment of inertia of the merry-go-round,
is the initial angular velocity of the merry-go-round,
is the moment of inertia of the merry-go-round and the child together and
is the final angular velocity.
First, we will find the moment of inertia of the merry-go-round using:
I = 
I = 
I = 359.375 kg*m^2
Where
is the mass and R is the radio of the merry-go-round
Second, we will change the initial angular velocity to rad/s as:
W = 0.520*2
rad/s
W = 3.2672 rad/s
Third, we will find the moment of inertia of both after the collision:



Finally we replace all the data:

Solving for
:

The correct answer is D: which is none of the above.
Hint: a wreckling ball contains pontential energy that acts like a pendulum
a pot of water contains pontential thermal energy