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1 year ago

Can Someone help me please…

Chemistry

1 answer:

erma4kov [3.2K]1 year ago

7 0

Answer:

1.Ecologists often estimate the size and density of. populations using quadrats and the mark-recapture method.

2. The two key components of ecosystem stability are resilience and resistance.

3.The availability of abiotic factors (such as water, oxygen, and space) and biotic factors (such as food) affect population

4. When the climate is changing in the colder direction it effects the planet in the opposite way than it does when it is changing in the warmer direction. Ad nauseam the contemporary, it’ll keep getting hotter and at a greater rate so the ecosystem is going to die.

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Starting with 2.50 mol of N2 gas (assumed to be ideal) in a cylinder at 1.00 atm and 20.0C, a chemist first heats the gas at con

arsen [322]

Answer:

a) $T_b=590.775k$

b) $W_t=1.08*10^4J$

d) $Q=3.778*10^4J$

d) $\triangle V=4.058*10^4J$

Explanation:

From the question we are told that:

Moles of N2 $n=2.50$

Atmospheric pressure $P=100atm$

Temperature $t=20 \textdegree C$

$t = 20+273$

$t = 293k$

Initial heat $Q=1.36 * 10^4 J$

Generally the equation for change in temperature is mathematically given by

$\triangle T=\frac{Q}{N*C_v}$

Where

$C_v=Heat\ Capacity \approx 20.76 J/mol/K$

$T_b-T_a=\frac{1.36 * 10^4 J}{2.5*20.76 }$

$T_b-293k=297.775$

$T_b=590.775k$

Generally the equation for ideal gas is mathematically given by

$PV=nRT$

For v double

$T_c=2*590.775k$

$T_c=1181.55k$

Therefore

$PV=Wbc$

$Wbc=(2.20)(8.314)(1181_590.778)$

$Wbc=10805.7J$

Total Work-done $W_t$

$W_t=Wab+Wbc$

$W_t=0+1.08*10^4$

$W_t=1.08*10^4J$

Generally the equation for amount of heat added is mathematically given by

$Q=nC_p\triangle T$

$Q=2.20*2907*(1181.55-590.775)\\$

$Q=3.778*10^4J$

Generally the equation for change in internal energy of the gas is mathematically given by

$\triangle V=nC_v \triangle T$

$\triangle V=2.20*20.76*(1181.55-293)k$

$\triangle V=4.058*10^4J$

3 0

2 years ago

Balance CH4+O2->CO2+H2O

malfutka [58]

Explanation:

I hope this helps Chemistry is so hard and I hate it

5 0

2 years ago

The melting points of alkaline earth metals are many times higher than those of the alkali metals. Explain this difference on th

7nadin3 [17]

The correct answer is higher melting point, bound by metal metal bonds.

While alkali metals only have one valence electron, alkaline earth metals have two. Metal to metal connections hold the metals together. Alkaline earth metals have a stronger metallic connection and a higher melting point because they have two valence electrons.

the characteristics that Group 2 metals excel in over Group 1 metals.

Initial Ionization Potential
Group 2 items are more difficult than group 1 elements.
Strong propensity to produce bivalent compounds

As a result, group 2 metals have stronger metallic bonding, which leads to increased cohesive energy and compact atom packing. This explains why group 2 metals are harder and have higher melting and boiling temperatures than group 1 metals.

To learn more about Group 2A(2) refer the link:

brainly.com/question/9431096

#SPJ4

3 0

1 year ago

What is a solution?

Keith_Richards [23]

Answer:

A !!

it a mix where everything is combined together

5 0

1 year ago