Answer:
CuO+2HCl>h2o+CuCl2
fe203+6hcl->2fecl3+3h2O
gọi CuO, fe2o3 lần lượt là x,y
80x+160y=10
2x+6y=0.35
giải phương trình ta dc hai số x,y(tính phương trình kia ra)
cuo ban đầu sẽ là :60*x=z
fe203 ban đầu sẽ là :10-z=
Explanation:
Answer: n-Butanol are converted using SN2 and tert-butanol is converted using SN1
Explanation: For the conversion of n-butanol into butyl chloride using Hydrogen Chloride the reaction would follow SN2 mechanism.
SN2 reaction mechanism occurs only in the case of primary substrates as it is a one step mechanism that happens in a concerted manner. It involves backside attack of nucleophile on the substrate such that the nucleophile attacks from the back side and leaving group leaves from the front side.
In this reaction since hydroxy group (OH) is not a good leaving group hence firstly we need to convert it into a good leaving group. When we treat n-butanol with HCl hydroxy group is protonated and now it turns into a good leaving group as it can leave as H₂O.
Cl⁻ here acts as nucleophile and now attacks the primary carbon center from the back side which contains the protonated hydroxy group as a leaving group.
In the case of tertiary butanol the reaction follows SN1 mechanism and it is 2 step mechanism.
In the first step hydroxy group is protonated and as it becomes a good leaving group it leaves and leads to the formation of a stable tertiary carbocation as an intermediate.
In the second step this intermediate carbocation is attacked by the Cl⁻ nucleophile which leads to the formation of tertiary butyl chloride.
Kindly find in attachment the reaction mechanism for both the reactions.
Answer: 1.49 moles of Nickel
Divide the given number of grams by 1mol of Nickel to get your answer.
Hope this helps!
Walking is what i think you are talking about
Each scientist could be working on the problem for different reason. Or, each scientist could be focused on different elements of the problem, concluding in different conclusions between the scientist.