Which object has a weight of about 22.5 n the book the rock the box the fish

If both mass and speed are doubled, what happens to its momentum?

puteri [66]

The general formula is: Momentum = (mass) x (speed)

I never like to just write a bunch of algebra without explaining it.
But in this particular case, there's really not much to say, and
I think the algebra will pretty well explain itself. I hope so:

Original momentum = (original mass) x (original speed)

New momentum = (2 x original mass) x (2 x original speed)

   = (2) x (original mass) x (2) x (original speed)

   = (2) x (2) x (original mass) x (original speed)

   = (4) x (original mass) x (original speed)

   = (4) x (original momentum).

7 0

3 years ago

A block slides down a rough ramp with a 30-degree incline as shown.

In-s [12.5K]

Answer:

Image 4 ?

Explanation:

5 0

4 years ago

An object is pushed from rest across a sheet of ice, accelerating at 8.0 m/s^2 [E] over a displacement of 1.05 m [E]. The object

tatiyna

Answer:

$D_T=18.567m$

Explanation:

From the question we are told that:

Acceleration $a=8.0 m/s^2$

Displacement $d=1.05 m$

Initial time $t_1=6.0s$

Final Time $t_2=2.5s$

Generally the equation for Velocity of 1.05 travel is mathematically given by

Using Newton's Law of Motion

$V^2=2as$

$V=\sqrt{2*6*1.05}$

$V=4.1m/s$

Generally the equation for Distance traveled before stop is mathematically given by

$d_2=v*t_1$

$d_2=3.098*4$

$d_2=12.392$

Generally the equation for Distance to stop is mathematically given by

Since For this Final section

Final velocity $v_3=0 m/s$

Initial velocity $u_3=4.1 m/s$

Therefore

Using Newton's Law of Motion

$-a_3=(4.1)/(2.5)$

$-a_3=1.64m/s^2$

Giving

$v_3^2=u^2-2ad_3$

Therefore

$d_3=\frac{u_3^2}{2ad_3}$

$d_3=\frac{4.1^2}{2*1.64}$

$d_3=5.125m$

Generally the Total Distance Traveled is mathematically given by

$D_T=d_1+d_2+d_3$

$D_T=5.125m+12.392+1.05 m$

$D_T=18.567m$

6 0

3 years ago

A capacitor consists of two square plates, 8.7 cm on a side, separated by a 2.0 mm air gap. How much energy would be stored in t

slavikrds [6]

Answer:

122.84 J

Explanation:

Since plate is square, area, A is given by $(8.7/100)^{2}=0.007569m^{2}$

The distance between plates, d, is given in the question as 2mm=0.002m

Charge on plate, Q, as given in the question is 240 $\mu c$

Assuming mica dielectric constant, k of 7

Capacitance, C is given by

C= $\frac {k\epsilon_{o}A}{d}=\frac {(7)(8.85*10^{-12})(0.007569)}{0.002}=2.34*10*^{-10}F$

Stored energy, E is given by

E= $\frac {Q^{2}}{2C}=\frac {(240*10^{-6})^{2}}{2*(2.34*10^{-10})}=122.84J$

Therefore, the stored energy is 122.84 J

5 0

3 years ago

A student observes rock layers that are folded and appear to be scratched. Select all of the geologic forces that might have cau

mrs_skeptik [129]

Rock layers are folded and appear to be scratched because of the plate tectonics and the glacial advance.

Answer: Option 1 and 2.

<u>Explanation:</u>

Plate tectonics and the glacial advance are the geological phenomenon which have the power to effect the layers of the rock. Because of these, there can be scratches on the layers of the rock and the layers of the rocks can be folded.

The huge mass of ice that is included in the glacier which may be of thickness of three to four kilometers is a lot to scratch the rocks. These glaciers are responsible for moving the rocks from their original position to a new place altogether.

7 0

3 years ago