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Scilla [17]
2 years ago
5

In an aqueous solution containing Mn(II) and Mn (IV) salts, which cation would you expect to be the more strongly hydrated

Chemistry
1 answer:
Alenkasestr [34]2 years ago
4 0

In an aqueous solution containing Mn(II) and Mn (IV) salts, Mn (IV) cation is expected to be the more strongly hydrated.

A chemical event called hydration occurs when two substances interact with water. Since Mn (IV) has a stronger cation with a +4 charge than Mn (II), it will draw more oxygen ions from the Mn(II) in aqueous solution. Mn(IV) will consequently be more intensely hydrated.

Another reason for this is that Mn(IV) ions are often smaller than ions. Now, if we take a look at the element that significantly influences hydration, it is ion size. Therefore, the ion will be more hydrated if it is smaller.

So, In an aqueous solution containing Mn(II) and Mn (IV) salts, Mn (IV) cation is expected to be the more strongly hydrated.

Learn more about hydration here;

brainly.com/question/15724859

#SPJ4

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Can Hydrocyanic acid be a Lewis Acid? What about a Lewis Base?
FinnZ [79.3K]

HCN is a Bronsted acid; it can dissociate into H+ and CN-. And H+ is a Lewis acid because it accepts election pairs. ... In order for H+ and CN- to be formed, Hydrogen in HCN donates its electrons to Carbon. So in this sense, Hydrogen is the lewis base and Carbon is the lewis acid.

8 0
3 years ago
A chemist dissolves of pure hydroiodic acid in enough water to make up of solution. Calculate the pH of the solution. Be sure yo
Gre4nikov [31]

Answer:

1.76

Explanation:

There is some info missing. I think this is the original question.

<em>A chemist dissolves 660.mg of pure hydroiodic acid in enough water to make up 300.mL of solution. Calculate the pH of the solution. Be sure your answer has the correct number of significant digits.</em>

<em />

Step 1: Calculate the molarity of HI(aq)

M = mass of solute / molar mass of solute × liters of solution

M = 0.660 g / 127.91 g/mol × 0.300 L

M = 0.0172 M

Step 2: Write the acid dissociation reaction

HI(aq) ⇄ H⁺(aq) + I⁻(aq)

HI is a strong acid, so [H⁺] = 0.0172 M

Step 3: Calculate the pH

pH = -log [H⁺]

pH = -log 0.0172

pH = 1.76

5 0
3 years ago
My teacher never taught me how to do this helpppp!!!!!!!
djverab [1.8K]
Just search up how much the weight is equal to another, then multiply it, thats what i do lol sorry if im no help
6 0
3 years ago
Which of the following is NOT a type of joint?
Setler79 [48]
B. is ur answer I bieleve
8 0
3 years ago
In the following equation:
Luda [366]

Answer:

FeCl₃

Explanation:

                 4FeCl₃  +   3O₂     => 2Fe₂O₃+ 6Cl₂

Given =>  7moles     9moles

A simple way to determine which reagent is the limiting reactant is to convert all given data to moles then divide by the respective coefficients of the balanced equation. The smaller value will be the limiting reactant.

                 4FeCl₃     +   3O₂     => 2Fe₂O₃+ 6Cl₂

Given =>  7/4 = 1.75*     9/3 = 3

*Smaller value => FeCl₃ is limiting reactant.  

NOTE: However, when working problems, one must use original mole values given.

   

7 0
3 years ago
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