Answer: The energy required to vaporize 12.5 g of liquid water is 28.2 kJ
Explanation:
Latent heat of vaporization is the amount of heat required to convert 1 gram of liquid into its vapor state without change in its temperature.
Given : The enthalpy of vaporization of water is 40.65 kJ/mol.
n = number of moles =
Thus 1 mole of water requires heat = 40.65 kJ
0.694 moles of water requires heat =
Thus the energy required to vaporize 12.5 g of liquid water is 28.2 kJ
2 K3PO4 + 3 BaCl2 = 6 KCl + Ba3(PO4)2
reaction type: double replacement
2 Al(OH)3 + 3 H2SO4 = Al2(SO4)3 + 6 H2O
reaction type: double replacement
2 HCl + K2CO3 = 2 KCl + H2O + CO2
i think there are two reactions here, so double replacement and decomposition
2 AgNO3 + Na2CO3 = Ag2CO3 + 2 NaNO3
reaction type: double replacement
2 Al2O3 = 4 Al + 3 O2
reaction type: decomposition
Answer:
The correct answer is option B.
Explanation:
Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.
The equation for the ionization of the magnesium hydroxide is given as:
xS yS
Here, S = concentration of compound dissolved in solvent via dissociation
Expression for the solubility product of will be:
As we can see,
- Higher the value of [S] more will be solubility of compound in a solvent.Hence, more soluble it will be.
- Lower the value of [S] less will be solubility of compound in a solvent.Hence, less soluble it will be.
Hence, the correct answer is option B.
Answer : The mass of in the solution is, 19.4 grams.
Explanation : Given,
Molarity of solution = 0.50 M
Volume of solution = 250 mL
Molar mass of = 155.6 g/mole
Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.
Formula used :
Now put all the given values in this formula, we get:
Therefore, the mass of in the solution is, 19.4 grams.