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1 year ago

The shoemaker-near spacecraft explored two asteroids, mathilde and eros. a big difference between them is that:________.

1 answer:

4 0

A big difference between Mathilde and Eros is that Mathilde represents a group of separate rocks whereas Eros is a solid rock.

<h3>What is an asteroid?</h3>

An asteroid is a celestial body composed of different types of rocky materials (generally clay but also silicate) and also metals (especially Fe).

An asteroid may have different sizes and some of them can be huge as dwarf planets that travel across the universe.

In conclusion, a big difference between Mathilde and Eros is that Mathilde represents a group of rocks whereas Eros is a solid rock.

Learn more about asteroids here:

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Select the false statement. A. Only materials that have never been part of a living thing can be recycled in nature. B. Matter f

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Option A is the false statement.

Only materials that have never been part of a living thing can be recycled in nature.

In actual all living and non living thing can be recycled in nature.

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2 years ago

Energy that flows from somthing with a higher temperature to something with a lower

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Answer:

Heat Transfer

Explanation:

This is called heat transfer. Heat transfer is the process in which energy flows from a matter that is higher in heat to a matter that is cooler, until the two matters reach the same temperature.

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2 years ago

2. a) A disc rotates about its axis at speed 25 revolutions per minute and takes 15 s to stop. Calculate the

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The statement shows a case of rotational motion, in which the disc <em>decelerates</em> at <em>constant</em> rate.

i) The angular acceleration of the disc ( $\alpha$ ), in revolutions per square second, is found by the following kinematic formula:

$\alpha = \frac{\omega_{f}-\omega_{o}}{t}$ (1)

Where:

$\omega_{o}$ - Initial angular speed, in revolutions per second.
$\omega_{f}$ - Final angular speed, in revolutions per second.
$t$ - Time, in seconds.

If we know that $\omega_{o} = \frac{5}{12}\,\frac{rev}{s}$ , $\omega_{f} = 0\,\frac{rev}{s}$ y $t = 15\,s$ , then the angular acceleration of the disc is:

$\alpha = \frac{0\,\frac{rev}{s}-\frac{5}{12}\,\frac{rev}{s}}{15\,s}$

$\alpha = -\frac{1}{36}\,\frac{rev}{s^{2}}$

The angular acceleration of the disc is $\frac{1}{36}$ radians per square second.

ii) The number of rotations that the disk makes before it stops ( $\Delta \theta$ ), in revolutions, is determined by the following formula:

$\Delta \theta = \frac{\omega_{f}^{2}-\omega_{o}^{2}}{2\cdot \alpha}$ (2)

If we know that $\omega_{o} = \frac{5}{12}\,\frac{rev}{s}$ , $\omega_{f} = 0\,\frac{rev}{s}$ y $\alpha = -\frac{1}{36}\,\frac{rev}{s^{2}}$ , then the number of rotations done by the disc is:

$\Delta \theta = 3.125\,rev$